Question

Compound EX4 reacts with Y2 giving two products: EX Y and XY. Calculate the E- X bond enthalpy if the reaction liberates 243.6 kJ/mol and other bond enthalpies are:
Y-Y 109 kJ/mol,
X-Y 123.1 kJ/mol and
E-Y 290 kJ/mol.
a. 547.7 kJ/mol
b. 60.5 kJ/mol
c. 234.7 kJ/mol
d. 20.6 kJ/mol
e. 176.9 kJ/mol

Answer 1

Answer:

Option B

Explanation:

From the question we are told that:

Equation

$EX_4+Y_2->EX_3Y+XY$

Bond enthalpies are:

 $Y-Y 109 kJ/mol,$

$X-Y 123.1 kJ/mol$  

$E-Y 290 kJ/mol.$

Generally the equation for the energy used to break E-X and Y-Y is mathematically given by

 $E_2=109+x$

Therefore

Total Energy Liberated is

 $E_T=E_1+E_2$

 $E_T=413.1+109+x$

 $E_T=304.1-x$

Since

  $E_T+E_I$

Therefore

 $304.1-x=243.6$

 $x=60.5kJ/mol$

Option B