1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elena L [17]
3 years ago
14

Compound EX4 reacts with Y2 giving two products: EX Y and XY. Calculate the E- X bond enthalpy if the reaction liberates 243.6 k

J/mol and other bond enthalpies are:
Y-Y 109 kJ/mol,
X-Y 123.1 kJ/mol and
E-Y 290 kJ/mol.
a. 547.7 kJ/mol
b. 60.5 kJ/mol
c. 234.7 kJ/mol
d. 20.6 kJ/mol
e. 176.9 kJ/mol
Chemistry
1 answer:
djyliett [7]3 years ago
6 0

Answer:

Option B

Explanation:

From the question we are told that:

Equation

EX_4+Y_2->EX_3Y+XY

Bond enthalpies are:

 Y-Y 109 kJ/mol,

X-Y 123.1 kJ/mol  

E-Y 290 kJ/mol.

Generally the equation for the energy used to break E-X and Y-Y is mathematically given by

 E_2=109+x

Therefore

Total Energy Liberated is

 E_T=E_1+E_2

 E_T=413.1+109+x

 E_T=304.1-x

Since

  E_T+E_I

Therefore

 304.1-x=243.6

 x=60.5kJ/mol

Option B

You might be interested in
Which statement Is true of chloroplasts? A. They transport glucose into the cell. B. They convert light energy into chemical ene
Lostsunrise [7]

answer is B. And chloroplast is only found is plant cells.

6 0
3 years ago
Read 2 more answers
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
What is the Method for distillation?
a_sh-v [17]
Distillation is a process of separating the component substances from a liquid mixture by selective evaporation and condensation. 
4 0
3 years ago
What part of the geocentric model was incorporated in the heliocentric model?
boyakko [2]
C. A central body is the center of the universe.
4 0
3 years ago
Two characteristics used to classify igneous rocks are texture and
kykrilka [37]
<span>Two characteristics used to classify igneous rocks are texture and </span>Mineral Grains

8 0
3 years ago
Read 2 more answers
Other questions:
  • What mass of manganese(II) chloride must react with sulfuric acid to release 52.5 mL of hydrogen chloride gas at STP?
    12·1 answer
  • During lab, you learned about exothermic and endothermic heats of solution. which compounds below could be used for a hot pack?
    13·1 answer
  • URGENT
    7·2 answers
  • Which balanced equation represents a single replacement reaction?
    13·1 answer
  • The water molecule H2O is polar because it contains two polar single bonds and A. its molecule has a linear shape. B. molecules
    11·2 answers
  • Balence chemical equations using coefficients<br><br> __Na + __Cl ------&gt;__NaCl
    5·1 answer
  • Hi i am from India which country are you from​
    9·2 answers
  • Which root word of the binary ionic compound ends with -ide?
    8·2 answers
  • Which of the following is not an alkali?
    8·1 answer
  • 3. If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!