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Viefleur [7K]
3 years ago
10

What happens to plankton during the spring bloom?Which organisms are consumers? (Select all that apply.) coyote, snail ,green al

gae, or bacteria
Physics
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

See explanation

Explanation:

Plankton refers to the small and microscopic organisms drifting or floating in the sea or fresh water, consisting chiefly of diatoms, protozoans, small crustaceans, and the eggs and larval stages of larger animals(Oxford dictionary).

The spring bloom is a sudden growth or increase in plankton abundance. It begins around the early spring and continues until late in the spring or sometimes even early in the summer.

One organism that is a consumer of plankton are the snails. One of the commonest snails that eat plankton are the Nerite Snails.

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A 25-ohm resistor at steady state draws a current of 10.8 amperes. its temperature is 310 k; the temperature of the surroundings
MA_775_DIABLO [31]

The total rate of entropy generation is 0.268 J/K.

Entropy, the degree of a gadget's thermal electricity consistent with unit temperature that is unavailable for doing useful paintings. due to the fact work is acquired from ordered molecular motion, the quantity of entropy is likewise a measure of the molecular sickness, or randomness, of a machine.

Resistance of resistor R = 25 ohm

the total rate of entropy generation ?

Current flowing through resistor I = 10 A

Heat generation due to resistance , Q = I2R = 100*25 = 2500 J

Resistor temperature T = 310 K

Surrounding temperature Ts = 300 K

Entropy change for Resistor, heat lost due to the resistance to the surrounding then Q = -ve

(ΔS)syst = - Q/T = - 2500 J/310K = - 8.064 J/K

Entropy change for the system: here heat gain from the resistor, Q = +ve

(ΔS)surr = +Q/Ts = 2500J/300K = 8.333 J/K

Total Entropy generation :

(ΔS)tot = (ΔS)syst + (ΔS) Surr = -8.064 + 8.333 = 0.268 J/K

Learn more about entropy here:- brainly.com/question/6364271

#SPJ4

3 0
2 years ago
Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m
Phantasy [73]

Answer:46.05 mm

Explanation:

Given

Power=260\ hp\approx 260\times 746=193.96\ KW

speed N=550\ rev/min

allowable shear stress (\tau )_{max}=15\ kpsi\approx 103.421\ MPa

Power is given by

P=\frac{2\pi NT}{60}

193.96=\frac{2\pi 550\times T}{60}

T=3367.6\ N-m

From Torsion Formula

\frac{T}{J}=\frac{\tau }{r}-----1

where J=Polar section modulus

T=Torque

\tau=shear stress

For square cross section

r=\frac{a}{2}

where a=side of square

J=\frac{a^4}{6}

Substituting the values in equation 1

\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}

a=0.04605\ m

a=46.05\ mm

7 0
3 years ago
A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,
Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

\int \overrightarrow{F}.d\overrightarrow{x}=\Delta  K.E

\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )

\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times  \left ( v^{2}-0^{2} \right )

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0
3 years ago
You drop a batitin a stationary elevator and the ball hits the floor in o 50 s. How long does it take for the ball to hit the fl
solmaris [256]

Answer:

option (a) 0.61 s

Explanation:

Given;

Time taken by the ball to reach the ground  = 0.50 s

Let us first calculate the distance through which the ball falls on the ground

from the Newton's equation of motion, we have

s=ut+\frac{1}{2}at^2

where,  

s is the distance

a is the acceleration

t is the time

here it is the case of free fall

thus, a = g = acceleration due to gravity

u =  initial speed of the ball = 0

on substituting the values, we get

s=0\times 0.50+\frac{1}{2}\times9.8\times0.50^2

or

s = 1.225 m

Now,

when the elevator is moving up with speed of 1.0 m/s

the initial speed of the ball = -1.0 m/s   (as the elevator is moving in upward direction)

thus , we have

s=ut+\frac{1}{2}at^2

or

1.225=-1.0\times\ t+\frac{1}{2}\times9.8t^2

or

4.9t^2 - t  - 1.225 = 0

or

t = 0.612 s

hence, the correct answer is option (a) 0.61 s

4 0
4 years ago
What type of machine would most likely be used to move buckets of the mineral pieces up to the surface of the Earth? a wedge a p
inessss [21]
The type of machine would be a pulley.
3 0
3 years ago
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