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Mumz [18]
3 years ago
8

Objects: A balloon full of helium in the air. Air- 1.27 kg/ml or Helium Balloon- 0.33 kg/ml

Physics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

Air has greater density.

The object will float.

Explanation:

Density of a body is defined as the mass of a body per unit volume of it.

Here, air has a density of 1.27 kg per ml and Helium balloon has a density of 0.33 kg per ml. This means that if volume is 1 ml, then the mass of air in that volume will be 1.27 kg and mass of Helium balloon in that same volume will be 0.33 kg.

Therefore, the mass of Helium balloon is lighter than that of air in a given volume. Hence, air is heavier and has a greater density.

A lighter density object always floats over a greater density body.

Hence, Helium balloon will float over air as Helium balloon is less dense than that of air.

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Charge is flowing through a conductor at the rate of 420 C/min. If 742 J. of electrical energy are converted to heat in 30 s., w
Y_Kistochka [10]

Answer:

3.53 V

Explanation:

Electric charge: The is the rate of flow of electric charge along a conductor.

The S.I unit of electric charge is C.

Mathematically it is expressed as,

Q = It ............................ Equation 1

Where Q = electric charge, I = current, t = time.

I = Q/t.......................... Equation 2

From the question, charge flows through the conductor at the rate of 420 C/mim

Which means in 1 min, 420 C of charge flows through the conductor.

Hence,

Q = 420 C, t = 1 min = 60 seconds

Substitute into equation 2

I = 420/60

I =7 A

Also

P = VI......................... Equation 3

Where P = power, V = potential drop, I = current.

V = P/I................... Equation 4

Note: Power = Energy/time

From the question, P = 742/30 = 24.733 W. and I = 7 A.

Substitute these values into equation 4

V = 24.733/7

V = 3.53 V

Hence the potential drop across the conductor =  3.53 V

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