Feb 16, 2012 ... How do you convert ethane to ethanoic acid? (with equation please). First you chlorinate it in presence of light. C2H6 + Cl2 ---hv -> C2H5Cl + ...
Preparation of ethanoic acid from ethane This free online course covers the preparation of ethanoic acid from ethane. The Contents tab displays all the lessons ...
he formation of the aldehyde is shown by the simplified equation: ... Note: The equation for the conversion of ethanol to ethanoic acid is worked out in detail ... Starting from ethanenitrile, you would therefore get a solution containing ethanoate ... Mar 3, 2012 ... As well as using a normal type of molecular formula to describe an organic .... In ethane the carbon atoms have the maximum number of hydrogen atoms bonded .... e.g. ethanoic acid and ethanol will produce ethyl ethanoate,.
Five hundred twenty million, three hundred and forty thousand. hope it helps!
Answer:
Explanation:
When there is difference between the concentration of the content of a cell and the solution surrounding the cell, there will be an Electrochemical gradient or Concentration gradient. Therefore, some solute will tend to move from the region of high concentration to the region of lower concentration through the cell membrane.
Such a movement is called Primary Active Transport
a) 1 mole of Ne
b) i/2 mole of Mg
c) 1570 moles of Pb.
d) 2.18125*10^-13 moles of oxygen.
Explanation:
The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.
6.23*10^23= 1/ 6.23*10^23
= 1 mole
The number of moles calculated by Avogadro's number in 3.01*10^23 of Mg
3.2*10^23=1/6.23*10^23
= 1/2 moles of Pb.
Number of moles in 3.25*10^5 gm of lead.
atomic weight of Pb=
n=weight/atomic weight
= 3.25*10^5/ 207
= 1570 moles of Pb.
Number of moles 4.50 x 10-12 g O
number of moles= 4.50*10^-12/16
= 2.18125*10^-13 moles of oxygen.
The answer for the following question is answered below.
- <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
Explanation:
Given:
Initial pressure of the gas = 1.34 atm
Initial temperature of the gas = 273 K
final temperature of the gas = 312 K
To solve:
Final temperature of the gas
We know;
From the ideal gas equation
P × V = n × R × T
So;
from the above equation we can say that
<em>P ∝ T</em>
= constant
= 
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
= 
= 1.76 atm
<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
