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3 years ago

10

Average velocity is different than average speed because calculating average velocity involves a)Distance b)Time c)Motion d)Disp

lacemnet

1 answer:

likoan [24]3 years ago

6 0

Answer:

The answer is D.

Explanation:

Average speed involve just distance and time but average velocity includes displacement and time.

(Correct me if I am wrong)

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Which kinds of objects emit visible light in the electromagnetic spectrum?1)all objects2)radioactive objects3)relatively cold ob

Lostsunrise [7]

Relatively hot objects emit visible light.
Some examples:
==> the wire coils in the toaster;
==> the spoon that you stuck in the flame on the stove;
==> the fine wire in the lightbulb when current goes through it.

VERY radioactive objects also do that. But if you're actually
standing there watching an object that's THAT radioactive,
then you're in big trouble.

8 0

3 years ago

Kirchhoff's Rules When applying Kirchhoff's rules, one of the essential steps is to mark each resistor with plus and minus signs

luda_lava [24]

Answer:

d. R4

Explanation:

Generally, the flow of current is always from the positive sign to the negative sign. In the resistors R1, R2, and R3, the direction of flow of current is from the positive sign to the negative sign. However, in the resistor R4, the direction of the flow of current is different from the conventional method. Therefore, the resistor R4 is marked wrongly.

8 0

2 years ago

Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this

maw [93]

Answer:

I = 578A

Explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by

$I = \frac{\epsilon_{max}}{R}$

$I = \frac{NBA\omega}{R}$

Where

I= current

N = Number of loops

$\omega =$ angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,

$I = \frac{(100)(1.3)(0.055)^2(2.5)}{1.7*10^{-3}}$

$I = 578A$

8 0

3 years ago

A field measuring 12 meters by 16 meters is to have a brick paver walkway installed all around it, increasing the total area to

kolezko [41]

Answer:

1.5 m

Explanation:

Length. L = 12 m

Width, W = 16 m

Area, A = 12 x 16 = 192 m^2

Let the width of pavement be d.

The new length, L' = 12 + 2d

the new width, W' = 16 + 2d

New Area, A' = L' x W' = (12 + 2d)(16 + 2d) = 192 + 56 d + 4d^2

Difference in area = A' - A

285 = 192 + 56 d + 4d^2 - 192

93 = 56 d + 4d^2

4d^2 + 56 d - 93 = 0

$d = \frac{-56\pm \sqrt{56^{2}+4\times 4\times 93}}{8}$

$d=\frac{-56\pm 87.72}{8}$ \

d = 1.5 m

Thus, the width of the pavement is 1.5 m.

6 0

3 years ago

Can Anyone help me with this?

agasfer [191]

1. Velocity

2. Time

3. Idk

4. Idk

5. D. I think it may be A. but I think D.

7 0

3 years ago

Read 2 more answers