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Brilliant_brown [7]
3 years ago
12

QUESTION 1

Physics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

2 * 10^5 pa

Explanation:

Pressure = Force / Area

Each thigh bone has a cross sectional area of 10cm²

Both thigh bones :

2 * 10cm² = 20cm²

To m² : 20 * (0.01)²

20 * 0.0001 m² = 0.002 m²

Force = mass * acceleration due to gravity(g)

g = 10m/s² ;

Force = 40 * 10 = 400N

Pressure = 400 N / 0.002 m²

Pressure = 200,000 N/m² = 2 * 10^5 pascal

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3 years ago
A student of mass 60.0 kg, starting at rest, slides down a slide 20.0 m long, tilted at an angle of 30.0° with respect to the ho
cricket20 [7]

Answer:

Explanation:

Reaction force of inclined surface

R = mgcos30

=60 x 9.8 x .866

= 509 N

Force of kinetic friction

= .12 x 509

= 61.08 N

b )

net force downwards = mgsinθ - μmgcosθ

acceleration = g sinθ - μgcosθ

9.8 sin30 - .12 x 9.8 x cos30

= 4.9 - 1.018

a= 3.88 m /s²

c )

v² = 2as

= 2 x  3.88 x 20

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8 0
3 years ago
A bolt is dropped from a bridge under construction, falling 97 m to the valley below the bridge. (a) how much time does it take
exis [7]
The first thing we have to do for this case is write the kinematic equationsto
 vf = a * t + vo
 rf = a * (t ^ 2/2) + vo * t + ro
 Then, for the bolt we have:
 100% of your fall:
 97 = g * (t ^ 2/2)
 clearing t
 t = root (2 * ((97) / (9.8)))
 t = 4.449260429
 89% of your fall:
 0.89*97 = g * (t ^ 2/2)
 clearing t
 t = root (2 * ((0.89 * 97) / (9.8)))
 t = 4.197423894
 11% of your fall
 t = 4.449260429-4.197423894
 t = 0.252

 To know the speed when the last 11% of your fall begins, you must first know how long it took you to get there:
 86.33 = g * (t ^ 2/2)
 Determining t:
 t = root (2 * ((86.33) / (9.8))) = <span> 4.19742389 </span>s
 Then, your speed will be:
 vf = (9.8) * (4.19742389) = 41.135 m / s

 Speed ​​just before reaching the ground:
 The time will be:
 t = 0.252 + <span> 4.197423894</span> = <span> 4.449423894</span> s
 The speed is
 vf = (9.8) * (4.449423894) =<span> <span>43.603</span></span> m / s

 answer
 (a) t = 0.252 s
 (b) 41,135 m / s
 (c) 43.603 m / s
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