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Naddika [18.5K]
3 years ago
14

Who served as an interpreter for Lewis and Clark during their trip out west?

Physics
2 answers:
AysviL [449]3 years ago
8 0

Sacagawea served as a interpreter

iogann1982 [59]3 years ago
7 0

Answer:Sacagawea

Explanation:

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Two masses 1.2kg and 1.8kg are connected to the ends of a rod of length 2m. Find the moment of inertia about the axes, 1)going t
frutty [35]

Answers: 1) 3 kg m²

                2) 2.88 kg m²

Explanation: <u> </u><u>Question 1</u>

                      I = m(r)²+ M(r)²

                      I = 1.2 kg × (1 m )² +1.8 kg ×(1 m )²

                    ∴  I =   3 kg m²

                       

                     <u> </u><u>Question 2 </u>

ACCORDING TO THE DIAGRAM DRAWN FOR QUESTION 2

we have to decide where the center of gravity (G) lies and obviously it should lie somewhere near to the greater mass.<em> (which is 1.8 kg). S</em>ince we don't know the distance from center of gravity(G) to the mass (1.8 kg) we'll take it as 'x' and solve!!

<u>moments around 'G' </u>

F₁ d ₁ = F₂ d ₂

12 (2-X) = 18 (X)

24 -12 X =18 X

∴  X = 0.8 m

∴ ( 2 - x ) = 1.2 m

∴ Moment of inertia (I) going through the center of mass of two masses,

⇒ I = m (r)² +M (r)²

⇒ I = 1.2 × (1.2)² + 1.8 × (0.8)²

⇒ I = 1.2 × 1.44 + 1.8 × 0.64

⇒ I = 1.728 + 1.152

⇒ ∴ I = 2.88 kg m²

∴ THE QUESTION IS SOLVED !!!

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8 0
3 years ago
Suppose that the sun shrank in size but that its mass remained the same. What would happen to the orbit of the earth?
Minchanka [31]

Answer:

Nothing

Explanation:

The radius of the orbit of the Earth does not depend on the radius of the sun.

In fact, the gravitational attraction between the Earth and the Sun provides the centripetal force that keeps the Earth in orbit:

G\frac{Mm}{r^2} = m\frac{v^2}{r}

where

G is the gravitational constant

M is the mass of the sun

m is the mass of the Earth

r is the radius of the orbit of the Earth

v is the orbital speed of the earth

Re-arranging the equation for r:

r=\frac{GM}{v^2}

Also,

v=\omega r

where \omega is the angular velocity of the Earth's orbit. So we can rewrite the equation as

r=\frac{GM}{\omega^2 r^2}\\r^3 = \frac{GM}{\omega^2}

As we see, the radius of the orbit of the Earth, r, does not depend on the mass of the Sun, so if the sun shrank in size, the orbit remains the same.

6 0
3 years ago
A truck going 15 km􏰀h has a head-on collision with a small car going 30 km􏰀h. Which statement best describes the situation
zlopas [31]

1. e) None of the above is necessarily true.

2.d) Without knowing the mass of the boat and the sack, we cannot tell.

5 0
3 years ago
After each charging, a battery is able to hold only 99% of the charge from the previous charging. The battery was used for 5 hou
Aloiza [94]

Answer:

500 hours

Explanation:

The sum of total hours over its lifetime will be given by

T=\frac {T_o}{1-r}

Where T is total time, r is rate in decimal and To is the original charge hours. Substituting the original charge hours with 5 hours and rate as 0.99 then the time will be

T=\frac {5\ hours}{1-0.88}=500\ hours

Therefore, the time is equivalent to 500 hours

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What do we call the point where molecules would have 0 kinetic energy?
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Absolute Zero is the name for when molecules have 0 kinetic energy.
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