The correct answer is a, lunar eclipse
<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision. </span>
<span>After collision... </span>
<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>
<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component) </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>
<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion. </span>
<span>Hope you understand!</span>
Answer:
0.1308
Explanation:
To keep the rider from sliding down, then the friction force
must at least be equal to gravity force 


where μ is the coefficient, N is the normal force acted by the rotating cylinder, m is the mass of a person and g = 9.81 m/s2 is the gravitational acceleration.
According to Newton's 3rd and 2nd laws, the normal force would be equal to the centripetal force
, which is the product of centripetal acceleration
and object mass m

Therefore


The centripetal acceleration is the ratio of velocity squared and the radius of rotation

Therefore

Answer:
Im pretty sure it's C
Explanation:
The answer A talks about constant speed, which does not correspond to Net Force. The answer B, talks about constant velocity, but talks about how much force apposes the box. The answer C talks about the value of the net force acting on the box, so im pretty sure the answer is C.