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dem82 [27]
3 years ago
10

Can you imagine scientific thought without these values? Why or why not?

Physics
1 answer:
tatyana61 [14]3 years ago
7 0
Without what values please be more specific 
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Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth o
postnew [5]
The density of silver is ρ = 10500 kg/m³ approximately.

Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet

Let A be the area.
Then, by definition,
m = (t*A)*ρ

Therefore
A = m/(t*ρ)
    = (1.7 kg)/ [(3.0 x 10⁻⁷ m)*(10500 kg/m³)]
    = 539.7 m²

Answer: 539.7 m²

8 0
3 years ago
Describe streak and cleavage and explain how they can be used to identify a mineral. PLEASE HELP.
timofeeve [1]
Streak means continuously
5 0
4 years ago
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3. A simple way to state Newton’s first law is:
MrRissso [65]

Explanation:

A simple way to state Newton's first law is:

For every action force, there is a reaction force which is equal in magnitude and opposite in direction.

4 0
3 years ago
Madison was driving at 40 mph and went 80 miles. How long did it take madison?
monitta
v=40\ mph\\\\s=80\ miles\\\\t=?\\--------------\\v=\frac{s}{t}\to vt=s\to t=\frac{s}{v}\\--------------\\t=\frac{80\ miles}{40\ mph}=2\ h\leftarrow Answer
3 0
3 years ago
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A thin beam of light of wavelength 50 μm (in the infrared portion of the em spectrum) goes through
Brut [27]

Solution :

Given :

Wavelength of the thin beam of light, λ = 50 μm

Distance of the screen from the slit, D = 3.00 m

Width of the fringe, Δy = ±8.24 mm

Therefore, width of the slit is given by :

$d=\frac{n \lambda D}{\Delta y}$

  $=\frac{2 \times 50 \times 10^{-9} \times 3}{2 \times 8.24 \times 10^{-3}}$

  = 0.000018203 m

  = 0.0182 mm

  = 0.018 mm

The intensity of light is given by :

$I=I_0\left(\frac{\sin \beta /2}{\beta/ 2}\right)^2$   , where $\beta=\frac{2 \pi D \sin \theta}{\lambda}$

$I=I_0\left(\frac{\sin \frac{\pi d \sin \theta}{\lambda}}{\frac{\pi d \sin \theta}{\lambda}}\right)^2$

$I=I_0\left(\frac{\sin \frac{\pi d y}{D\lambda}}{\frac{\pi d y}{D\lambda}}\right)^2$

Now, $\frac{dy}{D \lambda} = \frac{8.24 \times 10^{-3}\times 0.018 \times 10^{-3}}{4 \times 50\times 10^{-9}\times 4}$

               = 0.1854

               ≈ 0.18

$I=I_0\left(\frac{\sin 0.56}{0.56}\right)^2$

  $=I_0 \times 0.81$

  = 2  x0.81

  $= 1.62 \ W/m^2$

 

6 0
3 years ago
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