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nalin [4]
2 years ago
6

Coherent light of frequency f travels in air and is incident on two narrow slits. The interference pattern is observed on a dist

ant screen that is directly opposite the slits. The frequency of light f can be varied. For f = 5.60 × 1012 Hz there is an interference maximum for e = 60.0°. The next higher frequency for which there is an interference maximum at this Part A What is the separation d between the two slits? angle is 7.47 x 1012 Hz Express your answer with the appropriate units. HÀ Value d = _______.
Physics
1 answer:
svp [43]2 years ago
3 0

Answer:

A)        d = 6.1857 10⁻⁵ m

Explanation:

In the double-slit experiment the constructive interference is given by the expression

          d sin θ = m λ

          d =\frac{m \lambda  }{sin \theta}

let's use the relationship between speed, wavelength and frequency

          c = λ f

          λ = c / f

          λ = 3 10⁸ / 5.60 10¹²

          λ = 5.357 10⁻⁵ m

I do not know India in order of interference, we will assume that  m= 1

          d = 1  5,357 10⁻⁵ / sin 60

          d = 6.1857 10⁻⁵ m

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Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

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By using kinematics:

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But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

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Now we can calculate the final velocity:

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\theta=12.19^{\circ}

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