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irakobra [83]
3 years ago
12

How many atoms are in 3 moI of helium

Chemistry
2 answers:
disa [49]3 years ago
5 0
Mark Brainiest please

Answer:
1.8 x 10^24

One mole of helium has 6.02 x 10^23 atoms, thise number is also called Avogadro's number or constant.
If we need number of atoms for 3 moles so simply, multiply 3 by 6.02 x 10^23
so,
Number of atoms for 3 moles = 3 x ()
Number of atoms will be = 1.806x10^24
Mrac [35]3 years ago
3 0

Answer:

<h3>1.806x10^24</h3>

Explanation:

1 mole of helium gas contains 6.02 x10^23 helium atoms. So multiply this by 3 after solving the equation.

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An atom bonds with another atom. What is the best classification for this reaction?
OlgaM077 [116]

Explanation:

When an atom bonds with another atom then it results in the formation of a chemical bond.

This formation of bond could be due to transfer or sharing of electrons.

When a chemical bond is formed due to transfer of electrons then this type of bond is known as ionic bond.

When a chemical bond is formed due to sharing of electrons then this type of bond is known as covalent bond.

4 0
4 years ago
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if the pressure on a 3.0 liter sample of gas is doubled at constant temperature, the new volume will be
BabaBlast [244]
The new volume is 6.0 leters

7 0
3 years ago
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How many grams of NO can be made from 50 g of NH3?<br><br> 4 NH3 + 5 O2 → 6 H2O + 4 NO
Evgen [1.6K]
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4 0
2 years ago
1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction
nikklg [1K]

Answer:

H_{comb}=-4406kJ/mol

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol

Best regards.

4 0
4 years ago
Compute the number of grams(g) of lead in 22.5 moles of lead.
iogann1982 [59]

Answer:

4662 in grams

Explanation:

hope this helps :).

7 0
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