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3 years ago

How many atoms are in 3 moI of helium

2 answers:

5 0

Mark Brainiest please

Answer:
1.8 x 10^24

One mole of helium has 6.02 x 10^23 atoms, thise number is also called Avogadro's number or constant.
If we need number of atoms for 3 moles so simply, multiply 3 by 6.02 x 10^23
so,
Number of atoms for 3 moles = 3 x ()
Number of atoms will be = 1.806x10^24

Mrac [35]3 years ago

3 0

Answer:

Explanation:

1 mole of helium gas contains 6.02 x10^23 helium atoms. So multiply this by 3 after solving the equation.

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What do the COEFFICIENTS in a chemical reaction represent?

Alborosie

Answer:

the sum of the atoms or ions in the compound

5 0

3 years ago

Which of the following molecules would be the best hydrogen bond donor?

leva [86]

Answer: Option (d) is the correct answer.

Explanation:

When a hydrogen atom comes in contact with an electronegative atom then it results in the formation of a chemical bond.

More is the electronegativity of combining atom, more stronger will be the bond with hydrogen atom. As a result, the compound formed will not easily give up hydrogen atom upon dissociation.

Whereas less is the electronegativity of atom combining with hydrogen atom, easily it will donate the hydrogen atom upon dissociation.

Since, out of the given option sulfur (S) atom has low electronegativity as compared to oxygen and nitrogen atom.

Hence, $CH_{3}SH$ will easily donate hydrogen atom.

Thus, we can conclude that $CH_{3}SH$ molecule would be the best hydrogen bond donor.

4 0

3 years ago

Please help me

Dmitriy789 [7]

Answer:

divergent

Explanation:

I believe it is divergent.

7 0

3 years ago

1) For the following reaction, 8.44 grams of carbon (graphite) are allowed to react with 9.63 grams of oxygen gas.C(graphite)(s)

Yuki888 [10]

Answer:

The answers to the question are

(a) 13.24 g

(b) (O₂)

(2) 0.662 M/L

Explanation:

(a) To solve the question we write the equation as follows

C + O₂ → CO₂

That is one mole of graphite reacts with one mole of oxygen to form one mole of carbon dioxide

number of moles of graphite = 8.44/12 = 0.703 moles

number of moles of oxygen = 9.63/32 = 0.3009

However since one mole of graphite reacts with one mole of oxygen to form one mole of carbon dioxide, therefore, 0.3009 moles of oxygen will react with 0.3009 moles of carbon to fore 0.3009 moles of CO₂

The maximum mass of carbon dioxide that can be formed = mass = moles × molar mass

= 0.3009×44 = 13.24 g

(b) The formula for the limiting reagent (O₂)

Finding the limting reagent is by checking the mole balance of the reactants available to the moles specified in th stoichiometry of the reaction and selecting the reagent with the list number of moles

mass of excess reagent = 0.4021 × 12 = 4.8252 g

(2) The molarity is given by number of moles per liter of solution, therefore

molar mass of mgnesium iodide = 278.1139 g/mol, number of moles of magnesium iodide in 23 g = 23g/ 278.1139 g/mol= 8.3 × 10⁻² M

Therefore the moles in 125 mL = (8.3 × 10⁻² M)/(125 mL) = (8.3 × 10⁻² M)/(0.125 L) = 0.662 M/L

3 0

3 years ago

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Aleksandr [31]

Huh I don’t get it what is this

6 0

3 years ago