3 years ago

What is friction ridge skin?

Physics

1 answer:

kondor19780726 [428]3 years ago

7 0

It’s the skin on the palm of your hand including your fingers. As well as for your toes and soles of your feet.

You might be interested in

A 5,400 W motor is used to do work. If the motor is used for 640 s, about how much work could it do?

Fiesta28 [93]

The first option 8.4 J

5 0

2 years ago

Place least complex to most complex:

Reika [66]

Cell, tissue, organ, organ sytem, organism, population, community, ecosystem, biome.

7 0

3 years ago

Which of the following choices describes the type of image formed by a plane mirror?

Aleks04 [339]

Virtual upright and the same size

8 0

3 years ago

Read 2 more answers

A truck with 0.420-m-radius tires travels at 32.0 m/s. what is the angular velocity of the rotating tires in radians per second?

andrey2020 [161]

Angular velocity of the rotating tires can be calculated using the formula,

v=ω×r

Here, v is the velocity of the tires = 32 m/s

r is the radius of the tires= 0.42 m

ω is the angular velocity

Substituting the values we get,

32=ω×0.42

ω= 32/0.42 = 76.19 rad/s

= 76.19× $\frac{1}{2\pi} *60$ revolution per min

=728 rpm

Angular velocity of the rotating tires is 76.19 rad/s or 728 rpm.

4 0

3 years ago

Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of

vredina [299]

Answer:

The angular speed after 6s is $\omega = 1466.67s^{-1}$ .

Explanation:

The equation

$I\alpha = Fd$

relates the moment of inertia $I$ of a rigid body, and its angular acceleration $\alpha$ , with the force applied $F$ at a distance $d$ from the axis of rotation.

In our case, the force applied is $F = 22N$ , at a distance $d = 6cm =0.06m$ , to a ring with the moment of inertia of $I =mr^2$ ; therefore, the angular acceleration is