All categories

2 years ago

Will give brainliest to correct answer.

Physics

1 answer:

Darina [25.2K]2 years ago

4 0

Answer:

1.5X10^-4C

Explanation:

Expression for the electric force between the two charges is given by -

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = unknown

F=25N

q2 = 1.9x10^-6 C

r = 0.32 m

Substitute the given values in the above expression -

25=9x10^9 *(q1) * 1.9 x10^ -6/ (0.32m)^2

25= 17,100* (q1)/ 0.1024

multiply both sides by 0.1024 to get rid of the denominator

2.56=17,100*(q1)

Divide both sides by 17,100 to isolate q1

q1=1.5x10^-4C

You might be interested in

The results of a dart game were precise but not accurate. The accepted value of the game was the center of the dartboard. Which

hoa [83]

Answer:

The darts hit very different areas of the board.

Explanation:

8 0

2 years ago

Read 2 more answers

E-mail is usually a poor choice for the distribution of sensitive electronic files because __________. A. Paper copies seem more

iragen [17]

Answer: D.) e-mail is saved on the server that transfers it

Explanation:

3 0

1 year ago

Elements in the same periodic table group have the same___

Aliun [14]

Answer:

elements in the same periodic table group have the same valence electrons

6 0

3 years ago

A force Fof 40000 lbf is applied to rod AC the negative Y-direction. The rod is 1000 inches tall. A Force P of 25 lbf is applied

erastova [34]

Answer:

The answer is "effective stress at point B is 7382 ksi "

Explanation:

Calculating the value of Compressive Axial Stress:

$\to \sigma y =\frac{F}{A} = \frac{4 F}{( p d ^2 )} = \frac{(4 x ( - 40000 \ lbf))}{[ p \times (1 \ in)^2 ]} = - 50.9 \ ksi \\$

Calculating Shear Transverse:

$\to \frac{4v}{ 3 A} = \frac{4 (75 \ lbf + 25 \ lbf)}{ \frac{3 ( lni)^2}{4}}$

$= \frac{4 (100 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\ = \frac{400 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\= 0.17 \ ksi$

$= R \times 200 \ in - P \times 100 \ in = 12500 \ lbf \times\ in$

$\to \sigma' =[ s y^2 +3( t \times y^2 + t yz^2 )] \times \frac{1}{2}\\\\$

$= [ (-50.9)^2 +3((63.7)^2 +(0.17)^2 )] \times \frac{1}{2}\\\\=[2590.81+ 3(4057.69)+0.0289]\times \frac{1}{2}\\\\=[2590.81+12,173.07+0.0289] \times \frac{1}{2}\\\\=14763.9089\times \frac{1}{2}\\\\ = 7381.95445 \ ksi\\\\ = 7382 \ ksi$

8 0

2 years ago

Normal force is exerted _____to the surface of an object.

Elanso [62]

The normal force is always (underline, bold) is always perpendicular to the surface an object is sitting on. If the object is on an inclined plane, then the normal will not be vertical but it will be perpendicular to the angle of the incline.

The diagram below (left) shows a normal force (GH) that is not vertical, but it is perpendicular to the surface. The object on the right is the more usual normal a mass on a table top.

The vertical line on the right is the normal and it points up.

3 0

2 years ago

Read 2 more answers