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White raven [17]
3 years ago
12

Will give brainliest to correct answer.

Physics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

1.5X10^-4C

Explanation:

Expression for the electric force between the two charges is given by -

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = unknown

F=25N

q2 = 1.9x10^-6 C

r = 0.32 m

Substitute the given values in the above expression -

25=9x10^9 *(q1) * 1.9 x10^ -6/ (0.32m)^2

25= 17,100* (q1)/ 0.1024

multiply both sides by 0.1024 to get rid of the denominator

2.56=17,100*(q1)

Divide both sides by 17,100 to isolate q1

q1=1.5x10^-4C

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Question 20 (4 points)
irinina [24]

Explanation:

C is correct.

Newton second law states that force is directly proportional to acceleration with m being the constant of variation.

f _{net} = m(a)

So

250 = 50(a)

a = 5

A is wrong, the constant g only happens in free fall or in vertical direction

B and D are wrong due to the mathematical error or equation error

3 0
2 years ago
A circular swimming pool has a diameter of 18 m. The circular side of the pool is 3 m high, and the depth of the water is 1.5 m.
Dmitrij [34]

Answer:

A) 11223450 J

B) 18705750 J

Explanation:

Work done = force x distance moved.

Force of fluid at bottom of the pool = pghA

Where

P = density of water = 1000 kg/m3

g = acceleration due to gravity = 9.8 m/s2

h = depth of water = 1.5 m

A = area of pool of diameter d = 18 m

A = (¶d^2)/4 = (3.142 x 18^2)/4 = 254.5 m2

Total wall height of pool = 3 m

Force on pool bottom due to water is

F = 1000 x 9.8 x 1.5 x 254.5 = 3741150 N

A) work (in Joules) required to pump all of the water over the side

Height of wall H = 3 m

Work = F x H = 3741150 x 3 = 11223450 J

B) work (in Joules) required to pump all of the water out of an outlet 2m over the side?

Total height will be 2 + 3 = 5 m

Work = F x H = 3741150 x 5 =

18705750 J

8 0
3 years ago
What is the energy of one mole of photons with a wavelength of 418 nm? (h = 6.63 10-34 J . s, N = 6.02 1023.)
FrozenT [24]

Answer:E = 9.54×10-²Joules

Explanation:

Energy of photon E = hc/¶

Where ¶ is the wavelength

Given h = 6.63×10-³⁴ c= H = 6.02×10²³ ¶ = 418nm = 418 ×10^-9

Substituting the values in the formula

E = 6.63×10-³⁴×6.02×10²³/418 ×10^-9

E = 9.54×10-²Joules

8 0
4 years ago
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podryga [215]
For this problem, we are asked to calculate for the distance traveled. We set up the equations as follows:
Distance = 61 km/hr * (time + 20.8/60 s) Distance = 98.5 km/hr * time

We equate the two equations, then we can solve for the time spent on the trip. Hope this answers the question. Have a nice day.
8 0
3 years ago
The ratio of the speed of light in a medium to the speed of light in a vacuum is called its ______________ index.
Amiraneli [1.4K]
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Refractive index of water is 1.33
Refractive index of glass is about 1.4
3 0
3 years ago
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