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3 years ago

15

A bungee cord has a spring constant of 82.5 N/m. After jumping, a person oscillates with a period of 7.50 s. What is the mass of

the person?

1 answer:

Arada [10]3 years ago

3 0

Answer:

Explanation:

T = 2π √ (m/k)

T / 2π = √ (m/k)

T√k = 2π √m

(T√k) / 2π = √m

( (T√k) / 2π)^2 = m

m = ( (7.5√82.5) / 2π)^2

m = 117.66 Kg

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A first order reaction, A -> products, has a rate reaction of .00250 Ms-1 when [A] = . 484 M. (a) What is the rate constant,

tamaranim1 [39]

Answer: a) The rate constant, k, for this reaction is $0.00516s^{-1}$

b) No $t_{\frac{1}{2}}$ does not depend on concentration.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$A\rightarrow products$

Given: Order with respect to $A$ = 1

Thus rate law is:

a) $Rate=k[A]^1$

k= rate constant

$0.00250=k[0.484]^1$

$k=0.00516s^{-1}$

The rate constant, k, for this reaction is $0.00516s^{-1}$

b) Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{2.303}{k}\log\frac{100}{50}$

$t_{\frac{1}{2}}=\frac{0.69}{k}$

Thus $t_{\frac{1}{2}}$ does not depend on concentration.

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3 years ago

A magnifier has a magnification of 8 x. How far from the lens should an object be placed so that it’s virtual image is at the ne

larisa86 [58]

The distance of the object from the lens is 3.12 cm.

<h3>What is magnification?</h3>

Magnification is the process of of enlarging an apparent size of an object.

<h3>Object distance</h3>

The object distance is calculated using the following lens formula;

$M = \frac{V}{U}$

where;

M is the magnification
V is the image distance
U is object distance

$- 8 = \frac{-25}{U} \\\\U = \frac{-25}{-8} \\\\U = 3.12 \ cm$

Thus, the distance of the object from the lens is 3.12 cm.

Learn more about object distance here: brainly.com/question/24894435

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2 years ago

4. A motorist travels 406 km during a 9.0 hr period. What was the average speed in km/hr and m/s?

user100 [1]

Answer:

45.11 kmph and 12.530 m/s

Explanation:

Average speed = Total distance travelled / Total time taken

406/9 gives the answer in kilometers

And we convert it to m/s by multiplying it with 1000/3600

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3 years ago

A frame hanging on a wall is held by two cables. The tension in each cable is 30 N, and the cables make an angle of 45° with the

Vesna [10]

Answer:

(D) 42.4N

Explanation:

Since the frame is at rest, the net force acting on it must be 0. There are three forces acting on it: the gravity and the opposing forces of the two cables.

Since the gravity is a vertical force, we are only interested in the vertical components of the remaining forces. The net force equation is

F_net = 0 = F_g -2 * F_y

The vertical force of one cable (using the information in the drawing) is:

F_y = 30N * sin 45 deg = 21.21N

Now the weight can be determined:

0 = F_g - 2 * F_y

F_g= 2 * F_y = 2 * 21.21N = 42.4N

The weight of the frame is about 42.4N.

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3 years ago

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When energy is transformed, the amount of usable energy?

cricket20 [7]

Cannot be determined, I need more information.

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3 years ago