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goblinko [34]
3 years ago
11

2Na3N3 -> 2Na + 3N2 if 0.58 mol if NaN3 reacts, what mass of nitrogen would result

Chemistry
1 answer:
Ronch [10]3 years ago
8 0

Answer:

                      Mass = 24.36 g of N₂

Explanation:

                   The balance chemical equation for the decomposition of NaNO₃ is as follow;

                                           2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

                 2 moles of NaNO₃ produces  =  3 moles of N₂

So,

              0.58 moles of NaNO₃ will produce  =  X moles of N₂

Solving for X,

                      X = 3 mol × 0.58 mol / 2 mol

                      X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂

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Answer:

Noble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

Explanation:

Noble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

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In what zone of the ocean are thermal vents found? How are they related to organisms in this zone?
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the very bottom of the ocean and they are relevant by most of the animals feed off of the animals that come out of he vents

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3 years ago
Is Li has 7 valence electrons
jeka94
This is false. The amount of electrons in lithium (Li) is not 7, it is 3. There are 3 electrons in lithium.
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Consider a situation in which the enzyme is operating at optimum temperature and pH, and has been saturated with substrate. What
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Answer:Increase the enzyme concentration

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If the enzyme is saturated, it simply means that all the enzyme molecules present has been bound to substrates.

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4 0
3 years ago
The combustion reaction of isopropyl alcohol is given below: C 3 H 7 O H ( l ) + 9 2 O 2 ( g ) → 3 C O 2 ( g ) + 4 H 2 O ( g ) T
jek_recluse [69]

Answer:

the heat of formation of isopropyl alcohol is -317.82 kJ/mol

Explanation:

The heat of combustion of isopropyl alcohol is given as follows;

C₃H₇OH (l) +(9/2)O₂ → 3CO₂(g) + 4H₂O (g)

The heat of combustion of CO₂ and H₂O are given as follows

C (s) + O₂ (g) → CO₂(g) = −393.50 kJ

H₂ (g) + 1/2·O₂(g)   →  H₂O (l) = −285.83 kJ

Therefore we have

3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ which we can write as

3C (s) + 3O₂ (g) → 3CO₂(g) = −393.50 kJ × 3  =

4H₂ (g) + 2·O₂(g)   →  4H₂O (l) = −285.83 kJ × 4

3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ = +2006 kJ/mol

-1180.5 - 1143.32 +2006 = -317.82 kJ/mol

Therefore, the heat of formation of isopropyl alcohol = -317.82 kJ/mol.

3 0
3 years ago
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