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3 years ago

What are alkali metals

2 answers:

8 0

Alkali metals are any of the elements lithium, sodium, potassium, rubidium, cuisine, and francium, occupying Group 1A (1) of the periodic table. They are very reactive, electropositive, monovalent metals forming strongly alkaline hydroxides.

jeyben [28]3 years ago

7 0

Answer:

Alkali metals are highly reactive elements that appear to be silver and they are found in group 1 of the periodic table. It consists of lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). As you go further down the group, the more reactive they are. Those elements all react to water and air, so they must be kept in oil to preserve their state.

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What is the nucleus of an atom split

larisa [96]

In nuclear physics and nuclear chemistry, nuclear fission is either a nuclear reaction or a radioactive decay process in which the nucleus of an atom splits<span> into smaller parts (lighter </span>nuclei<span>). Hope this helps</span>

4 0

3 years ago

Read 2 more answers

PLEASE HURRY AND SHOW WORK

IgorC [24]

Answer:

The answer to your question is P = 1.64 atm

Explanation:

Data

Volume = 2.5 x 10⁷ L

Temperature = 22°C

Pressure = ?

Moles = 1.7 x 10⁶

R = 0.082 atm L/ mol°K

Process

1.- Convert temperature to °K

Temperature = 22 + 273

= 295°K

2.- Use the Ideal gas law to solve this problem

PV = nRT

- Solve for P

P = nRT / V

- Substitution

P = (1.7 x 10⁶)(0.082)(295) / 2.5 x 10⁷

- Simplification

P = 41123000 / 2.5 x 10⁷

- Result

P = 1.64 atm

3 0

3 years ago

An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f

Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

Mass of carbon, $C$ :

$\frac{32.18}{100}\times 223.94 = 72.06 g$

Mass of hydrogen, $H$ :

$\frac{4.5}{100}\times 223.94 = 10.08 g$

Mass of chlorine, $Cl$ :

$\frac{63.32}{100}\times 223.94 = 141.79 g$

Now, the number of each element in the unknown compound is determined by the formula:

$number of moles = \frac{given mass}{molar mass}$

Number of moles of $C$ :

$number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole$

Number of moles of $H$ :

$number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole$

Number of moles of $Cl$

$number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole$

Dividing each mole with the smallest number of mole, to determine the empirical formula:

$C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}$

$C_{1.5}H_{2.5}Cl_{1}$

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is $C_{3}H_{5}Cl_{2}$ .

Empirical mass = $12\times 3+1\times 5+2\times 35.5 = 112 g/mol$

In order to determine the molecular formula:

n = $\frac{molar mass}{empirical mass}$

n = $\frac{223.94}{112} = 1.99 \simeq 2$

So, the molecular formula is:

$2\times C_{3}H_{5}Cl_{2} = C_{6}H_{10}Cl_{4}$

6 0

3 years ago

What does thermal energy refer to?

ludmilkaskok [199]

my answer is D sorry if I'm wrong

5 0

3 years ago

Read 2 more answers

Suppose protons were emitted rather than electrons. How would this affect the experiment?

Vera_Pavlovna [14]

Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .

The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects. We can conserve the electric energy which is equal to the qe .

The kinetic energy = 1/2 $mv^{2}$

Now changing the electric potential energy into kinetic energy

v = √2qe/m

The mean velocity of proton will be less then mean velocity electron .

To learn more about proton

brainly.com/question/1252435

#SPJ4

6 0

2 years ago