Decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.
As we know that rate of reaction is directly proportional to the concentration of the reactant.
If we increase the concentration of H2 then the rate of reaction increases. So, we keep it constant. Therefore this option is wrong.
By removing the H₂O from the reaction vessel as it almost make no change in the reaction. This can be pursuited the reaction in which product again converted into product.
By increasing the temperature we increases the rate of reaction and equilibrium shift in the forward direction.
Thus, we concluded that by decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.
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From the mole ratio of the reaction as given in the equation of the reaction, the mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is 310.245 g.
<h3>What mass of calcium chloride can be produced from 5.59 mol of hydrochloric acid?</h3>
The mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is determined from the equation of the reaction.
The equation of the reaction is given below:
Ca²⁺ (aq) + 2 HCl (aq) ---> CaCl₂ (s) + H₂ (g)
From the equation of the reaction, the mole ratio of HCL and calcium chloride is 2 : 1
Therefore, moles of calcium chloride that can be produced will be:
The moles of calcium chloride = 5.59 moles * 1/2
The moles of calcium chloride = 2.795 moles
The mass of calcium chloride produced = moles * molar mass
Molar mass of calcium chloride = 111 g/mol
Mass of calcium chloride produced = 2.795 * 111
Mass of calcium chloride produced = 310.245 g
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Answer:
0.007756M KHP; 0.0009695 moles NaOH reacts; 0.03488M NaOH.
Explanation:
Potassium hydrogen phthalate, KHP, is a salt used as standard to determine concentration of basic solutions as NaOH solutions.
To find molarity of the KHP solution we need to convert mass of KHP to moles and divide this in 125mL = 0.125L:
<em>Moles KHP -Molar mass: 204.22g/mol-:</em>
0.198g * (1mol / 204.22g) = 0.0009695 moles KHP
<em>Molarity:</em>
0.0009695 moles KHP / 0.125L = 0.007756M KHP
NaOH reacts with KHP as follows:
NaOH + KHP → Na⁺ + KP⁻ + H₂O
That means 1 mole of NaOH reacts per mole of KHP, that means moles of NaOH that reacts are = Moles of KHP added:
0.0009695 moles NaOH reacts
In 27.80mL = 0.02780L the NaOH was contained. Molarity is:
0.0009695 moles NaOH / 0.02780L =
0.03488M NaOH
Ba! It is a metal and wants to lose 2 electrons ASAP
That what I found 0.1 M NaCl
