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Dennis_Churaev [7]
3 years ago
9

You carry a 7.0 kg bag of groceries above the level floor at a constant velocity of 75 cm/s across a room that is room. How much

work do you do on the bag in the process?
Physics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

1.97J

Explanation:

Given parameters:

Mass of the groceries = 7kg

velocity of the bag = 75cm/s

Unknown:

Work done to move the bag  = ?

Solution:

Work done is the force applied to move a body through a distance in a specific direction:

     Work done = Force x distance

In this case, the work done is the kinetic energy applied in pulling the bag.

Kinetic energy is the energy in motion of a body.

 Work done  = kinetic energy = \frac{1}{2} m v^{2}

where m is the mass

           v is the velocity

Now, convert the velocity from cm/s to m/s

   100cm = 1m

 75\frac{cm}{s }  x \frac{1m}{100cm}  = 0.75m/s

 Work done  = \frac{1}{2} x 7 x 0.75² = 1.97J

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The density of the substance is<u> 10.5 g/cm³.</u>

The jewelry is made out of <u>Silver.</u>

Density ρ is defined as the ratio of mass <em>m</em> of the substance to its volume V<em>. </em> The cylinder contains a volume <em>V₁ of water</em> and when the jewelry is immersed in it, the total volume of water and the jewelry is found to be V₂.

The volume <em>V</em> of the jewelry is given by,

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Substitute 48.6 ml for <em>V₁ </em>and 61.2 ml for V₂.

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\rho =\frac{m}{V}

Substitute 132.6 g for <em>m</em> and 12.6 ml for <em>V</em>.

\rho =\frac{m}{V}\\ =\frac{132.6 g}{12.6 ml} \\ =10.5 g/ml

Since 1 ml=1 cm^3,

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From standard tables, it can be seen that the substance used to make the jewelry is <u>silver</u><em><u>, </u></em>which has a density 10.5 g/cm³.



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Answer:

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Answer:

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Explanation:

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