Determina la fuerza de acción que se presenta entre dos cuerpo cuyas masas son 500 Kg y 900 Kg, si ambos cuerpos se encuentran s
1 answer:
Answer:
F = 7.50 10⁻⁶ N
Explanation:
The force of attraction between two bodies is given by the law of universal gravitation
F =
where m₁ and m₂ are the masses of the hides, r the distance that separates them and G the constant of attraction that is worth 6.67 10⁻¹¹ N m²/kg²
let's calculate
F = 6.67 10⁻¹¹ 500 900/2²
F = 7.50 10⁻⁶ N
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Complete Question:
In the "before" part of Fig. 9-60, car A (mass 1100 kg) is stopped at a traffic light when it is rear-ended by car B (mass 1400 kg). Both cars then slide with locked wheels until the frictional force from the slick road (with a low ?k of 0.15) stops them, at distances dA = 6.1 m and dB = 4.4 m. What are the speeds of (a) car A and (b) car B at the start of the sliding, just after the collision? (c) Assuming that linear momentum is conserved during the collision, find the speed of car B just before the collision.
Answer:
a) Speed of car A at the start of sliding = 4.23 m/s
b) speed of car B at the start of sliding = 3.957 m/s
c) Speed of car B before the collision = 7.28 m/s
Explanation:
NB: The figure is not provided but all the parameters needed to solve the question have been given.
Let the frictional force acting on car A, ............(1)
Since frictional force is a type of force, we are safe to say .......(2)
Equating (1) and (2)
a) Speed of A at the start of the sliding
b) Speed of B at the start of the sliding
Let the speed of car B before collision =
Momentum of car B before collision =
Momentum after collision =
Applying the law of conservation of momentum:
To solve this problem we will apply the concepts related to Newton's second law that relates force as the product between acceleration and mass. From there, we will get the acceleration. Finally, through the cinematic equations of motion we will find the time required by the object.
If the Force (F) is 42N on an object of mass (m) of 83000kg we have that the acceleration would be by Newton's second law.
Replacing,
The total speed change
we have that the value is 0.71m/s
If we know that acceleration is the change of speed in a fraction of time,
We have that,
Therefore the Rocket should be fired around to 1403.16s