Determina la fuerza de acción que se presenta entre dos cuerpo cuyas masas son 500 Kg y 900 Kg, si ambos cuerpos se encuentran s
1 answer:
Answer:
F = 7.50 10⁻⁶ N
Explanation:
The force of attraction between two bodies is given by the law of universal gravitation
F =
where m₁ and m₂ are the masses of the hides, r the distance that separates them and G the constant of attraction that is worth 6.67 10⁻¹¹ N m²/kg²
let's calculate
F = 6.67 10⁻¹¹ 500 900/2²
F = 7.50 10⁻⁶ N
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Answer:
1000 Joules per second.
Explanation:
To lift that much grass 5 meters higher than it was before the tractor did work that is the product of the (force needed to overdo gravity) and (displacement):
Power is work over the amount of time:
The final velocity of the 15 kg mass is 18.33 m/s.
<h3>Conservation of linear momentum</h3>The final velocity of the 15 kg mass can be determined by applying the principles of conservation of linear momentum as follows;
Where;
- m₁ is the mass of the first object = 25 kg
- u₁ is the initial velocity of the first object = 15 m/s
- m₂ is the mass of the second object = 15 kg
- u₂ is the initial velocity of the second object = -10 m/s
- v₁ is the final velocity of the first object = -2 m/s
- v₂ is the final velocity of the second object
Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238