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Ierofanga [76]
3 years ago
13

Determina la fuerza de acción que se presenta entre dos cuerpo cuyas masas son 500 Kg y 900 Kg, si ambos cuerpos se encuentran s

eparados a una distancia de 2 m. Datos Fórmula Sustitución y Operaciones Resultado
Physics
1 answer:
Rainbow [258]3 years ago
7 0

Answer:

F = 7.50 10⁻⁶ N

Explanation:

The force of attraction between two bodies is given by the law of universal gravitation

          F = G \frac{m_1m_2}{r^2}

where m₁ and m₂ are the masses of the hides, r the distance that separates them and G the constant of attraction that is worth 6.67 10⁻¹¹  N m²/kg²

let's calculate

          F = 6.67 10⁻¹¹   500  900/2²

          F = 7.50 10⁻⁶ N

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PART A:
olga55 [171]

Answer:

4 m/s^{2}

Explanation:

From Equilibrium of forces, The Tension in string is cancelled by the Weight (product of mass and acceleration due to gravity) of the body acting downwards.

The Net force = Mass * Acceleration.

Since Net Force = 20 Newton, Mass = 5kg, therefore;

20 = 5kg * acceleration. Dividing the RHS and LHS of the equation by 5, we have;

Acceleration = \frac{20}{5} which gives 4.

Note: RHS means Right Hand Side.

         LHS means Left Hand Side.

 

7 0
3 years ago
Calculate the acceleration of a bus that goes
Svet_ta [14]

The acceleration of the bus is 1.11 meters per second square to the direction of motion

Explanation:

Acceleration is the rate of change of velocity

The formula of the acceleration is a=\frac{v_{2}-v_{1}}{t} , where

  • v_{1} is the initial velocity
  • v_{2} is the final velocity
  • t is the time

A bus that goes  from 10 km/h to a speed of 50 km/h in 10 seconds

→ v_{1} = 10 km/h

→ v_{2} = 50 km/h

→ t = 10 seconds

Change the unite of the time from seconds to hour

→ 1 hour = 60 × 60 = 3600 seconds

→ 10 seconds = \frac{10}{3600}=\frac{1}{360} hour

Substitute these values in the formula of the acceleration above

→ a=\frac{50-10}{\frac{1}{360}}

→ a = 14400 km/h²

To change the unit of acceleration to meter per second change the

  kilometer to meter and the hour to seconds

→ 1 km = 1000 m

→ 1 hour = 3600 seconds

→ a=\frac{14400*1000}{(3600)^{2}}=\frac{10}{9}

→ a = 1.11 m/sec².

The acceleration of the bus is 1.11 meters per second square to the direction of motion

Learn more:

You can learn more about the acceleration in brainly.com/question/6323625

#LearnwithBrainly

4 0
3 years ago
What type of clouds are associated with low pressure?
Naddik [55]
Cumulus and cumulonimbus<span />
5 0
3 years ago
The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting
Monica [59]
Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. </span><span>The equation for </span>gravitational potential energy<span> is GPE = mgh. 

GPE = 1200(1.6)(350) = 672000 J

Hope this answers the question. Have a nice day.</span>
8 0
3 years ago
Read 2 more answers
A 55-kg woman is wearing high heels. If each heel has a circular cross-section 6.0 mm in diameter and she puts all her weight on
bogdanovich [222]

Answer:

The pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²

Explanation:

Given;

mass of the woman, m = 55 kg

diameter of the circular heel, d = 6.0 mm

radius of the heel, r = 3.0 mm = 0.003 m

Cross-sectional area of the heel is given by;

A = πr²

A = π(0.003)²

A = 2.8278 x 10⁻⁵ m²

The weight of the woman is given by;

W = mg

W = 55 x 9.8

W = 539 N

The pressure exerted by the woman on the floor is given by;

P = F / A

P = W / A

P = 539 / (2.8278 x 10⁻⁵ )

P = 1.9061 x 10⁷ N/m²

Therefore, the pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²

5 0
3 years ago
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