Answer:
266 tickets
Step-by-step explanation:
Ratio of adult tickets to child tickets is 4 : 3
So, if we think of these as "parts", there are 4 parts adult tickets and 3 parts child tickets.
In total there is:
4 + 3 = 7 parts
Now, given 152 adult tickets. If there are 4 parts of adult tickets, how much is each part worth?
152/4 = 38
Total amount of tickets is 7 of these "parts", so total number of tickets is:
38 * 7 = 266 tickets
18 |16 | 13 | 10 | 9.5 | 8.5 | 7.5 | 6
9.75 is the FINAL answer
Answer: z score = 0.00714
Step-by-step explanation: the value of test statistics is gotten using the standard normal distribution table.
Z= 2.45 has area to the left (z<2.45) and area to the right (z>2.45).
Level of significance α is the probability of committing a type 1 error. The area under the distribution is known as the rejection region and it is the area towards the right of the distribution.
The table I'm using is towards the left of the distribution.
But z>2.45 + z<2.45 = 1
z> 2.45 = 1 - z<2.45
But z < 2.45 = 0.99286
z > 2.45 = 1 - 0.99286
z >2.45 = 0.00714
Hence the test statistics that would produce the least type 1 error is 0.00714
The digit 7 would be ten times greater than the digit 7 in number 0.9750 in any number with 7 in the tenths place, for example
0.723
0.7669
0.775
1.7899
Owner would lose out on $100
