Answer:
Two complex roots.
Step-by-step explanation:
F(x)=2x^4 +5x^3 - x^2 +6x-1
is a polynomial in x of degree 4.
Hence F(x) has 4 roots. There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.
Use remainder theorem to find the roots of the polynomial.
F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0
There is a change of sign in F from 0 to 1
Thus there is a real root between 0 and 1.
Similarly by trial and error let us find other real root.
F(-3) = -1 and F(-4) = 94
SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.
Other two roots are complex roots since no other place F changes its sign
Answer:
41
Step-by-step explanation:
BIDMAS
[5 x (4 + 6) - 9]
Brackets first
4 + 6 = 10
[5 x (10) - 9]
Multiply next
5 x 10 = 50
Subtract last
50 - 9 = 41
Answer:
negative 5/4
Step-by-step explanation:
The integers are x, x + 2 and x + 4
x + x + 2 + x + 4 = 72
3x + 6 = 72
3x = 72 - 6 = 66
x = 66/3 = 22
The least consecutive integer is 22
The second consecutive integer is 24
Therefore, the numbers are 22, 24 and 26
(a-25b)(a+4b)=0
Use the quadratic formula or complete the square by looking at the factors
