293 is a prime number, so you can't divide it in factors
Answer:
(9sqrt13)/13
Step-by-step explanation:
Answer:
Mean = 30.68
Standard deviation = 6.095
Two standard deviations above the mean = 42.87
Step-by-step explanation:
Given the following data :
21; 21; 22; 23; 24; 24; 25; 25; 28; 29; 29; 31; 32; 33; 33; 34; 35; 36; 36; 36; 36; 38; 38; 38; 40
Mean = Σ(x) / n
n = 25
Σ (X) = 767
Mean (m) = 767 / 25
Mean (m) = 30.68
Standard deviation : sqrt[Σ(x - m) / n]
Using a calculator :
Standard deviation = 6.095 ( 2 decimal places)
2 standard deviations above the mean :
Mean + 2(standard deviation)
Mean + 2(6.095)
30.68 + 12.19
30.68 + 12.19
= 42.87
Answer:
x^2 -10x -96 =0
Step-by-step explanation:
Subtract the zeros from x in factors
(x - -6) (x-16)
(x+6) (x-16)
Set these equal to zero since they are zeros
(x+6) (x-16) =0
FOIL
x^2 -16x+6x -96 =0
x^2 -10x -96 =0
