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liraira [26]
3 years ago
5

How many grams of magnesium oxide are formed if 20.9 grams of Mg and 15.2 g of O2 react.

Chemistry
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

Mass of magnesium oxide formed = 35.1 g

Explanation:

Given data:

Mass of Mg = 20.9 g

Mass of O₂ = 15.2 g

Mass of magnesium oxide formed = ?

Solution:

Chemical equation:

2Mg + O₂     →   2MgO

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 20.9 g/ 24 g/mol

Number of moles = 0.87 mol

Number of moles of O₂:

Number of moles = mass/molar mass

Number of moles = 15.2 g/ 32 g/mol

Number of moles = 0.475 mol

Now we will compare the moles of MgO with magnesium and oxygen.

                Mg          :         MgO

                  2           :           2

                0.87        :         0.87

                  O₂         :         MgO

                     1         :            2

                   0.475   :        2/1×0.475 = 0.95  

Number of moles of MgO formed by Mg are less thus Mg will limiting reactant.

Mass of MgO:

Mass = number of moles × molar mass

Mass = 0.87 mol × 40.3 g/mol

Mass = 35.1 g

                 

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Answer:

None of the options are correct. The correct answer is:

56.67g

Explanation:

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Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

From the equation,

6g of H2 produced 34g of NH3.

Therefore, 10g of H2 will produce = (10 x 34)/6 = 56.67g of NH3

Therefore, 56.67g of NH3 are produced

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3 years ago
1826.5g of methanol (CH3OH), molar mass = 32.0 g/mol is added to 735 g of water, what is the molality of the methane 0.0348 m 1.
Snowcat [4.5K]

Answer:

Molality = 1.13 m

Explanation:

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of CH_3OH = 26.5 g

Molar mass of CH_3OH = 32.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{26.5\ g}{32.04\ g/mol}

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Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )

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3 years ago
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