The temperature of liquid nitrogen (LN), an inert cryogenic fluid, is 196 °C (320 °F). To drop the temperature of the concrete as much as is possible without causing it to freeze, LN is directly injected by lances into the batch water storage tank, the aggregate, or the mixer.
<h3>What is Cryopreservation ?</h3>
Cryopreservation is the process of preserving live cells, tissues, and other biological samples by placing them in a deep freezer at extremely low temperatures. The sample is typically stored at 196°C or lower. All of a cell's biological processes come to an end at such low temperatures, and the cell dies.
- Cells and tissues intended for transplantation are frequently stored via cryopreservation. A extremely stable ultra-low temperature environment is provided by liquid nitrogen. It is therefore employed for long-term storage.
Learn more about Cryopreservation here:
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The three broad classes of elements are:
Metals
Metalloids
Nonmetals
24 minus 8 is 16
5 times 60 is 300
300 times 16 is 4800.
She winks 4800 times a day
Answer:
1.125 moles of H2S
Explanation:
From 2HCl(aq) + ZnS(s) ---------> H2S (g) + ZnCl2 (aq)
From the reaction equation;
2 moles of HCl produces 1 mole of H2S
Therefore 2.25 moles of HCl will produce 2.25 ×1/2 = 1.125 moles of H2S
Recall that it was explicitly stated in the question that ZnS is the reactant in excess. This implies that HCl is the limiting reactant and controls the amount of product obtained.
Answer:- The natural abundance of 
is 0.478 or 47.8% and 
is 0.522 or 52.2% .
Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:
Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)
We have been given with atomic masses for and as 150.919860 and 152.921243 amu, respectively. Average atomic mass of Eu is 151.964 amu.
Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of as n then the abundance of would be 1-n .
Let's plug in the values in the formula:
151.964=150.919860n+152.921243-152.921243n
on keeping similar terms on same side:
negative sign is on both sides so it is canceled:
The abundance of is 0.478 which is 47.8%.
The abundance of is = 
= 0.522 which is 52.2%
Hence, the natural abundance of is 0.478 or 47.8% and is 0.522 or 52.2% .
