The enthalpy change accompanying the reaction of 0.95 g of S is -11.85 kJ
Given
ΔH° for the reaction is -790 kJ
Required
The enthalpy change
Solution
Reaction
2S (s) + 3O₂(g) = 2SO₃ (g)
mol of S(MW=32 g/mol) :
For 2 mol S, the entalphy = -790kJ
The enthalpy change for 0.03 mol :
Answer:
c
Explanation:
and that's bc it will not share stay the same
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A is your answer