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uysha [10]
3 years ago
11

Wat would happen if a feather and a ball were released from the same height at the same time? Gravity Experiments for Kids – Sci

ence Experiments for Kids
Physics
1 answer:
solniwko [45]3 years ago
6 0

Answer:

They would land at the same time

Explanation:

They would land at the same exact time.

As weird, impossible and unbelievable as it appears. When in a vacuum, every weight, body and material when released from the same height would land on the ground at the same time. This also means that like in the question, a feather and a ball would land at the same time. And just for illustrations as well, a feather and a car would land at the same time as well.

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A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f
igor_vitrenko [27]

The formula for half-life is:

A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope.  Let's plug in our values to the equation:

A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.

4 0
3 years ago
What is the power of a 650N force that moves an object 75cm in 0.63s?​
Ratling [72]

Answer:

<u>Power</u><u> </u><u>is</u><u> </u><u>7</u><u>7</u><u>3</u><u>.</u><u>8</u><u> </u><u>watts</u>

Explanation:

{ \rm{power =  \frac{force \times distance}{time} }} \\  \\ { \rm{power =  \frac{650 \times 0.75}{0.63} }} \\  \\ { \rm{power = 773.8 \: watts}}

5 0
2 years ago
If the diameter of a radar dish is doubled, what happens to its resolving power assuming that all other factors remain unchanged
kirill115 [55]

Answer:

      θ’ = θ₀ / 2

we see that the resolution angle is reduced by half

Explanation:

The resolving power of a radar is given by diffraction, for which we will use the Rayleigh criterion for the resolution of two point sources, they are considered resolved if the maximum of diffraction of one coincides with the first minimum of the other.

The first minimum occurs for m = 1, so the diffraction equation of a slit remains

        a sin θ = λ

in general, the diffraction patterns occur at very small angles, so

        sin θ = θ

          θ = λ / a

in the case of radar we have a circular aperture and the equation must be solved in polar coordinates, which introduces a numerical constant.

        θ = 1.22 λ /a

In this exercise we are told that the opening changes

         a’ = 2 a

we substitute

          θ ‘= 1.22  λ / 2a

          θ' = (1.22 λ / a) 1/2

          θ’ = θ₀ / 2

we see that the resolution angle is reduced by half

8 0
3 years ago
What is the total displacement of a child who walks 4m south 2m north 5m south and 5 m north?
seropon [69]
Your answer is going to be 2m south
3 0
3 years ago
After walking across a carpeted floor in socks, Jim brings his finger near a metal doorknob and receives a shock. what does that
8_murik_8 [283]
When you touch<span> a doorknob (or something else made of metal), which has a positive charge with few electrons.</span>
6 0
3 years ago
Read 2 more answers
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