Answer:
The value of the equilibrium constant Kc is 5.45
Explanation:
The "Law of Mass Action" states:
"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."
This constant was called the equilibrium constant. For a reaction:
aA + bB ⇄ cC + dD
the equilibrium constant Kc is:
![Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
In this case, the balanced reaction is:
2 H₂S → 2 H₂ + S₂
So, the equilibrium constant Kc is:
![Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_%7B2%7D%20%5D%5E%7B2%7D%20%2A%5BS_%7B2%7D%20%5D%20%7D%7B%5BH_%7B2%7D%20S%5D%5E%7B2%7D%20%20%7D)
The equilibrium concentrations are
- [H₂S] =0.25 M
- [H₂]= 0.88 M
- [S₂]= 0.44M
Replacing in the definition of equilibrium constant:
Solving:
Kc= 5.45
<u><em>The value of the equilibrium constant Kc is 5.45</em></u>
<u><em></em></u>
Displacement is zero. Displacement is in reference to the starting and ending positions, so starting and ending in the same place would cause a net displacement of zero. Distance, however, is not zero. It is a measurement of the total amount moved, so if the object left the starting position, the distance is automatically not zero.
Answer:
mole fraction of NaCl = 0.03145.
mole fraction of water = 0.9686.
Explanation:
- Mole fraction is an expression of the concentration of a solution or mixture.
- It is equal to the moles of one component divided by the total moles in the solution or mixture.
- The summation of mole fraction of all mixture components = 1.
mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).
<em>no. of moles of NaCl = mass/molar mass </em>= (6.87 g)/(58.44 g/mol) = 0.1176 mol.
<em>no. of moles of water = mass/molar mass</em> = (65.2 g)/(18.0 g/mol) = <em>3.622 mol.</em>
<em></em>
∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.
<em>∵ mole fraction of NaCl + mole fraction of water = 1.0.</em>
∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.
Yes if a molecule with a COOH group is called a carboxylic acid.
hope that helps
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