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lora16 [44]
3 years ago
11

How many atoms of fluorine are in 5.6x10^22 molecules of MgF2

Chemistry
1 answer:
bija089 [108]3 years ago
7 0

Answer:

1.12x10²³ atoms of F

Explanation:

A molecule is a group of 2 or 3 atoms that are bonded by electrostatic charges.

In 1 molecule of MgF2 there are 2 atoms of fluorine and 1 atom of magnesium.

Thus, there are 2 atoms of fluorine per molecule of MgF2. In 5.6x10²² molecules:

5.6x10²² molecules MgF2 * (2 atoms Fluorine / 1 molecule MgF2) =

<h3>1.12x10²³ atoms of F</h3>
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Where did they start water conservation in tamil nadu . short answer
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Explanation:

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Traditional Rainwater Conservation methods of Tamil Nadu

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Kudimaramathu

Kudimaramathu is one of the old traditional practice of stakeholders participating in the maintenance and management of irrigation systems. During earlier days, citizens of a village used to actively participate in maintaining the water bodies of their village by deepening and widening the lakes and ponds and restoring the water bodies back to their original form. The silt, rich in nutrients, collected in the process would be used by the farmers themselves in their field. A sense of collective ownership ensured the continued survival of the water bodies.

6 0
3 years ago
What factors are requierd for cloning
ioda
In mammals and amphibians? An enucleated egg, a donor nucleus (preferably from an early developmental stage such as a blastocyst), and a means to stimulate the egg to be activated as if it had just been fertilized (poking with a needle is sometimes enough) 

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What is the total pressure of a gas mixture containing partial pressures of
Advocard [28]

Answer:

1.54 atm

Explanation:

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So,P= P1 + P2 + P3

Therefore, P=0.23+0.42+0.89

=1.54 atm

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6. This part of Earth's atmosphere blocks the sun's harmful rays. (4 points)
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7 0
3 years ago
Read 2 more answers
a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
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