3 years ago

Need help please this is physics work

Physics

1 answer:

SashulF [63]3 years ago

5 0

Answer:

the density of gasoline is about 0.7 kg per latest a URL 50 litre of gasoline to your car and when feeling it what is the mass of the same amount of gasoline 2144 to 86 kg answer

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Describe the compressions and rarefactions of a longitudinal wave

4vir4ik [10]

Compressions are the areas of high pressure while rarefractions are low pressure area

5 0

4 years ago

Part A Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 8.7 m whose uniform depth is 1.8 m . Express y

Sphinxa [80]

Answer:

17.66 kPa

Explanation:

The volume of water in the swimming pool is the product of its dimensions

V = 30 * 8.7 * 1.8 = 469.8 cubic meters

Let water density $\rho = 1000 kg/m^3$ , and g = 9.81 m/s2 we can calculate the total weight of water in the swimming pool

$W = mg = \rho V g = 1000 * 469.8 * 9.81 = 4608738 N$

The area of the bottom

A = 30 * 8.7 = 261 square meters

Therefore the pressure is its force over unit area

$P = F/A = 4608738 / 261 = 17658 N/m^2$ or 17.66 kPa

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4 years ago

A student throws a water balloon with speed v0 from a height h = 1.82 m at an angle θ = 29° above the horizontal toward a target

3241004551 [841]

Answer:

$v_o = 7.76 m/s$

Explanation:

As we projected the balloon at speed vo at an angle of 29 degree

so the two component of velocity is given as

$v_x = v_ocos29 = 0.875 v_o$

$v_y = v_o sin29 = 0.485 v_o$

now we know that in x direction we have

$d = v_x t$

$7.5 = 0.875 v_o t$

$v_o t = 8.57$

in y direction we have

$- 1.82 = (0.485 v_o) t - \frac{1}{2}gt^2$

$-1.82 = 0.485(8.57) - 4.9 t^2$

$t = 1.1 s$

now we have

$v_o = 7.76 m/s$

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4 years ago

Question 24 of 33 Which of the following is an example of uniform circular motion? A. A car speeding up as it goes around a curv

Fofino [41]

Answer:

Uniform Circular Motion is the Movement or Rotation of an Object along a circular Path at constant speed.

OPTION C IS YOUR ANSWER!.

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3 years ago

Express the length of a marathon run of<br> 26 mi 385 yd in meters.<br> Answer in units of m.

hjlf

Answer:

1 mi = 5280 ft * 12 in/ft = 63360 in

A convenient conversion factor (to remember) is 1 m = 39.37 in

63360 in / (39.37 in / m) = 1609.3 m

26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m

6 0

3 years ago