Answer:
Explanation:
Parameters given;
Magnetic field intensity, B = 1.4 T
Speed of proton, v =
Mass of proton, m =
Charge of proton, q =
To find the acceleration of the proton, we first need to find the force exerted by the magnetic field on the proton:
F = q * v * B
F = * * 1.4
F =
This is the force exerted by the magnetic field on the proton. The force exerted by the proton has the same magnitude but an opposite direction as the force exerted by the magnetic field. Hence, = -
The force exerted by the proton is the product of its mass and acceleration. Hence, we can find its acceleration:
= ma
a = F/m
The magnitude, |a|, will be:
|a| =| |
|a| =
The magnitude of the acceleration of the proton is |a|
Vf = final velocity
Vi = initial velocity
g = acceleration due to gravity
t = time
Vf = Vi + gt
Vf = 0 + (9.8)(7.80)
Vf = 76.44 m/s
It’s hypothesis because it’s not backed up but it’s evidence for it to be true
Il existe troi types de rayons produits lors de la désintégration des éléments radioactifs:
-- "particules alpha" . . . noyaux d'hélium, composés chacun de 2 protons et 2 neutrons
-- "rayons bêta" ou "particules bêta" . . . flux d'électrons
-- "rayons gamma" . . . rayonnement électromagnétique avec les longueurs d'onde les plus courtes connues et l'énergie la plus élevée