1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Darya [45]
3 years ago
8

What is the momentum of a 1,985-kg car going 32.5 m/s?

Physics
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

64512.5 m/kg

Explanation:

p=mv

p=1985 x 32.5

=64512.5

You might be interested in
Calculate the acceleration of a 90-kg skydiver with a net force of -883 N
Helen [10]
F=ma, in this case your force=-883 N and mass = 90 kg. F/m=a therefore acceleration=-883/90=-9.81 m/s/s
6 0
3 years ago
From the Bohr Model diagram, assuming the atom is neutral, what element is represented by the diagram? A) Argon B) Chlorine Elim
viktelen [127]

The actual answer is B) Chlorine

According to the Bohr Model diagram, the atom has seventeen electrons. This makes it Chlorine.


Sorry if i'm late!!

5 0
3 years ago
Read 2 more answers
The cytoplasm of a cell consists mainly of water.
ankoles [38]
Deal! The answer is true
5 0
3 years ago
Read 2 more answers
The wave length of violet light rounded to the nearest nanometer is a __ nm
nataly862011 [7]
Wavelength= speed / frequency 

so.....3× 10^8 / 7.26×10^14
= .413× 10^(-6)

in scientific notation= 4.13×10^(-7) 

in nanometer = 413 nm
6 0
3 years ago
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

T^2 \propto R^3

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

T^2 \propto R^3

T^2 = kR^3

Substituting the values, we get the value of constant k for mars.

687^2 = k\times (2.279 \times 10^{11})^3

k = 3.92 \times 10^{-29}

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

365^3 = 3.92\times 10^{-29} R^3

R^3 = 3.39 \times 10^{33}

R= 1.50 \times 10^{11}\;\rm m

Hence we can conclude that the distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

6 0
2 years ago
Other questions:
  • How does the theory of natural selection explain the diversity of life?
    10·1 answer
  • A 3.00 kg object is fastened to a light spring, with the intervening cord passing over a pulley. The pulley is frictionless, and
    15·1 answer
  • Que es electromagnetico?
    6·1 answer
  • Why isn't a pendulum a wave
    6·1 answer
  • Three forces that act on a roller coaster:
    6·2 answers
  • Which feature of a soundwave is related to pitch
    13·2 answers
  • The atomic number of yttrium is 39. The atomic mass of one of its isotopes is 89. How many neutrons are in an atom of this isoto
    10·1 answer
  • Starting from your campsite you walk 3.0 km east, 6.0 km north, 1.0 km east, and then 4.0 km west. How far are you from your cam
    5·1 answer
  • Un móvil se encuentra en la posición inicial x0 = 22 m, y se mueve con velocidad 5 m/s. Calcula la posición en la que se encuent
    8·1 answer
  • A car starts from rest and after 7.0 seconds it is moving at 42 m/s. What is the car's average acceleration?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!