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2 years ago

2. What is the average height in cm for plants in group 2? * 38 cm 56 cm 97 cm 114 cm

Chemistry

1 answer:

Nina [5.8K]2 years ago

6 0

Answer:

76.25cm

Explanation:

38cm + 56cm +97cm +114cm = 305cm

305cm÷4 = 76.25cm

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What important material is absorbed by your digestive system besides water

Leto [7]

Answer:

The monosaccharides, amino acids, bile salts, vitamins, and other nutrients are absorbed by the cells of the intestinal lining

Explanation:

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2 years ago

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8! How many moles are in 73410" molecules of KMO,

Cloud [144]

There’s no element with symbol M

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3 years ago

in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125

PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0

3 years ago

What is the concentration of H+ ions at a pH = 11?

natta225 [31]

Answer:

$\huge 1 × {10}^{-11} \: \: M$

Explanation:

The pH of a solution can be found by using the formula

$pH = - log [ {H}^{+} ]$

Since we are finding the H+ ions we find the antilog of the pH

So we have

$11 = - log({H}^{+}) \\ {H}^{+} = {10}^{ - 11}$

We have the final answer as

$1 × {10}^{-11} \: \: M$

Hope this helps you

6 0

2 years ago

How many moles are in 2.98x10^23 particles?

Novosadov [1.4K]

Answer:

$\boxed {\boxed {\sf 0.495 \ mol}}$

Explanation:

We are given a number of particles and asked to convert to moles.

<h3>1. Convert Particles to Moles </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.

So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.

$\frac { 1 \ mol }{6.022*10^{23 } \ particles}}$

We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.

$2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}$

The units of particles cancel.

$2.98*10^{23} *\frac { 1 \ mol }{6.022*10^{23 } }}$

$\frac { 2.98*10^{23}}{6.022*10^{23 } }} \ mol$

$0.4948522086 \ mol$

<h3>2. Round</h3>

The original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.

For the number we found, 3 sig figs is the thousandth place.

The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.

$0.495 \ mol$

2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>

3 0

2 years ago