Question

If the total mechanical energy of the block spring system is 512 J, what is the amplitude for this oscillation?

Answer 1

Answer:

A = 2.26 m

Explanation:

Given that,

The total mechanical energy of the block spring system is 512 J

Let the spring constant, k = 200 N/m

We need to find the amplitude for this oscillation. The mechanical energy of the spring mass system is given by :

$E=\dfrac{1}{2}kA^2$

k is spring constant

$A=\sqrt{\dfrac{2E}{k}} \\\\A=\sqrt{\dfrac{2\times 512}{200}} \\A=2.26\ m$

So, the amplitude of the oscillation is 2.26 m