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sweet-ann [11.9K]
3 years ago
9

Force has _____. magnitude direction gravity weight

Physics
2 answers:
Contact [7]3 years ago
7 0

Answer:

magnitude

Explanation:

Aleksandr-060686 [28]3 years ago
6 0

Answer:

A and B

Explanation:

Force has both magnitude and direction since it is a vector quantity

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A 500 gram mass attached to a horizontal spring
Daniel [21]
Is that a question? .
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8 0
3 years ago
How many molecules are there in 39 grams of water
Llana [10]

Answer:

39 g H2O contains 1.3 ×1024molecules H2O.

Explanation:

8 0
3 years ago
The melting point of pure water is _____.<br><br> 32°C<br><br> 100°C<br><br> 0°C<br><br> 212°C
BabaBlast [244]

Answer:

0°C and 32°F

Explanation:

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3 0
3 years ago
Read 2 more answers
Which of the following is a vector quantity?
gizmo_the_mogwai [7]

Answer:

B. 30 m down

Explanation:

In physics we have two types of quantities:

- Scalar quantity: it is a quantity which only has a magnitude (e.g: mass and time are scalar quantities, since they only have a magnitude)

- Vector quantity: it is a quantity which has both a magnitude and a direction (e.g: velocity is a vector quantity, since it has a magnitude (the speed) and a direction)

In this problem, we have:

A. 100 ounces of water  --> scalar (this is a volume, which has only a magnitude)

B. 30 m down  --> vector (this is a displacement, which has both a magnitude (30 m) and a direction (down)

C. 88 mi/s  --> scalar (this is a speed, which has only a magnitude)

D. 45 gallons in a bucket --> scalar (this is a volume, which has only a magnitude)

So, the correct option is B.

4 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
3 years ago
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