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suter [353]
3 years ago
9

An important difference between fuel cells and batteries is that batteries _______. Select the correct answer below: do not requ

ire a continuous source of fuel require a continuous source of fuel are able to expel products are constantly resupplied with reactants
Chemistry
1 answer:
aliya0001 [1]3 years ago
4 0

Answer: the correct option is that batteries (do NOT require a continuous source of fuel).

Explanation:

A battery can be classified as an electrochemical cell that has the ability to produce electric current. They do NOT require a continuous supply of fuel because it contains all the reactants needed to produce electricity. Below are some examples of batteries that are commonly used:

--> Primary battery: This is a single use battery because it can't be recharged. A typical example is the dry cell.

--> Secondary battery: This type of battery can be recharged. They are used as a power source for smartphones, electronic tablets, and automobiles.

A FUEL CELL is known as a device that converts chemical energy into electrical energy. Fuel cells are similar to batteries but require a continuous source of fuel, often hydrogen. They will continue to produce electricity as long as they are constantly resupplied with reactants. Hydrogen fuel cells have been used to supply power for satellites, space capsules, automobiles, boats, and submarines.

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If an object has a density of 25 g/cm and a mass of 100 grams, what is its volume? O 40 cm3 0.25 cm 4 cm3 125 cm3​
xz_007 [3.2K]
<h3>Answer:</h3>

4 cm³

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Chemistry</u>

<u>Gas Laws</u>

Density = Mass over Volume

  • D = m/V
<h3>Explanation:</h3>

<u>Step 1: Define</u>

D = 25 g/cm³

m = 100 g

<u>Step 2: Solve for </u><em><u>V</u></em>

  1. Substitute variables [D]:                    \displaystyle 25 \ g/cm^3 = \frac{100 \ g}{V}
  2. Multiply <em>V</em> on both sides:                  \displaystyle V(25 g/cm^3) = 100 \ g
  3. Isolate <em>V</em>:                                            \displaystyle V = 4 \ cm^3
8 0
3 years ago
What is the random mixing of gas molecules called?
ruslelena [56]
The random mixing of gas molecules is called A.)Diffusion
4 0
3 years ago
The heat of vaporization for water is 40. 7 kJ/mol. How much heat energy must 150. 0 g of water absorb to boil away completely?
netineya [11]

The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.

The heat of vaporization has been the amount of heat required to vaporize 1 gram of liquid.

The heat required for the vaporization has been given as:

Q=m\Delta H_{vap}

<h3 /><h3>Computation for the Heat of vaporization</h3>

The heat of vaporization of water has been given as, \Delta H_{vap}=40.7\;\rm kJ/mol

The mass of water sample has been, m=150\;\rm g

Substituting the values for the heat energy absorbed, <em>Q:</em>

<em />

<em />Q=150\;\times\;40.7\;\rm kJ\\&#10;\textit Q=6,105\;kJ

The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.

Learn more about heat of vaporization, here:

brainly.com/question/2427061

3 0
3 years ago
When of alanine are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing poin
vitfil [10]

Answer:

16.5 g

Explanation:

The van't Hoff factor is a relation between the ideal value of a solution's colligative properties and the observed colligative properties.

Check the attached files for detailed solution

7 0
4 years ago
When 16.9 g KOH is dissolved in 90.8 g of water in a coffee-cup calorimeter, the temperature rises from 18.5 °C to 34.27 °C. Wha
juin [17]

Answer:

-431.5 J/g

Explanation:

Mass of solution = Mass of solute + mass of solvent

Solute is KOH while solvent is water.

Mass of KOH = 16.9 g

Mass of water = 90.8 g

Mass of solution = 16.9 + 90.8

                          = 107.7 g

Change in temperature (Δt) = 34.27 - 18.5

                                           = 16.2 °C

Heat required to raise the temperature of water is released by dissolving KOH.

Therefore,

Heat released by KOH = m × s× Δt

                                    = 107.7 × 4.18 × 16.2

                                    = 7293 J

Heat released by per g KOH = 7293 J/16.9 g

                                             = 431.5 J/g

As heat is released therefore, enthalpy change would be negative.

Enthalpy change of KOH = -431.5 J/g

4 0
3 years ago
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