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sasho [114]
3 years ago
5

45-428-(15+3) 2+245-428(18)445-428×18×445-428×7245-30,816-30,771​

Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

Have u answered it already or u want help or u want to be sure of the answer

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11. In AWTY, if mZW is five less than twice mZY and mZX is 21 more than m_Y find the measure
wolverine [178]

9514 1404 393

Answer:

  angles (W, X, Y) = (77°, 62°, 41°)

Step-by-step explanation:

<u>Given</u>:

  ΔWZY

  ∠W = 2(∠Y) -5°

  ∠X = ∠Y +21°

<u>Find</u>:

  ∠X, ∠Y, ∠W

<u>Solution</u>:

Using angle measures in degrees, we have ...

  ∠X + ∠Y + ∠Z = 180

  (∠Y +21) +∠Y + (2(∠Y) -5) = 180

  4(∠Y) +16 = 180 . . . . . simplify

  ∠Y +4 = 45 . . . . . . . . . divide by 4

  ∠Y = 41 . . . . . . . . . . . . subtract 4

  ∠W = 2(41) -5 = 77

  ∠X = 41 +21 = 62

The angle measures of angles (W, X, Y) are (77°, 62°, 41°), respectively.

7 0
2 years ago
Solve the equation x2 + 7x = 30.​
Law Incorporation [45]

Answer:

2*7=14+6=30 points plz

5 0
2 years ago
Mr. Mole left his burrow and started digging his way down at a constant rate.
Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute = \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},

\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow = -18 - 5(-2.4) = -18+12 = -6.

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

5 0
3 years ago
Read 2 more answers
WHAT IS THE LENGTH!!!
Murljashka [212]

The figure is a trapezoid (or trapezium), and the exact length of the trapezoid is 5 units

<h3>How to determine the length?</h3>

The figure is a trapezoid with the following parameters:

Area = 107.95

Base= 12

Height = 12.7

Length = x

The area of a trapezoid is:

Area = 0.5 * (Base + Length) * Height

So, we have:

0.5 * (12 + Length) * 12.7 = 107.95

Evaluate the product

(12 + Length) * 6.35 = 107.95

Divide both sides by 6.35

12 + Length = 17

Subtract 12 from both sides

Length =  5

Hence, the length of the trapezoid is 5 units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

6 0
1 year ago
How to do two step equlaity work problems
USPshnik [31]

Answer:

can you be more specific? give a problem

Step-by-step explanation:

5 0
3 years ago
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