Answer:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
Answer:
1.17
Explanation:
Given that,
The refractive index of ice wrt air = 1.31
The refractive index of rock salt wrt air = 1.54
We need to find the refractive index of rock salt with respect to ice.
We know that,
refractive index = (speed of light in air or vaccum)/( speed of light in that medium)
So,
The speed of light in ice = c/(1.31)
The speed of light in rock salt = c/(1.54)
So, the refractive index of rock salt with respect to ice is :
![\mu=\dfrac{1.54}{1.31}\\\\=1.17](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7B1.54%7D%7B1.31%7D%5C%5C%5C%5C%3D1.17)
So, the required refractive index of rock salt wrt ice is 1.17.
Given Information:
frequency = 1240 Hz
width = a = 1.13 m
speed of sound = c = 344 m/s
Required Information:
angle = θ = ?
Answer:
θ = 14.18 rad
Explanation:
We can find out the angle relative to the centerline perpendicular to the doorway by using the following relation
sin(θ) = λ/a
Where λ is the wavelength of the sound wave and a is width
λ = c/f
Where c is the speed of the sound and f is the frequency
λ = 344/1240
λ = 0.277
sin(θ) = λ/a
θ =sin⁻¹(λ/a)
θ =sin⁻¹(0.277/1.13)
θ =sin⁻¹(0.277/1.13)
θ = 14.18 rad
Answer:
check the point where the output device's field wiring is connected to the output rack. ( C )
Explanation:
Given that an indicator light on the output module is indicating that a signal has been sent to the output point where the failed single output device is connected , the best line of action to properly indicate the output device that has filed in the PLC system, is to check the point where the output device's field wiring is connected to the output rack in the PLC system.
A PLC system is a computer control system ( especially Industrial ) that helps in the monitoring the states of input and output devices in an industry.
Answer:
Explanation:
The <u>initial</u> vertical velocity is 540sin55° = 442.342103... 442 m/s
The <u>initial</u> horizontal velocity is 540cos55° = 309.731275... 310 m/s
In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.