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3 years ago

Describe two features of the graph which show that the law is obeyed.

Physics

2 answers:

disa [49]3 years ago

4 0

The graph is linear and increases

Marizza181 [45]3 years ago

3 0

The graph is a linear
It is a increases

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If the tension in a rope is increased, what will happen to the speed of a wave traveling through the rope?

Lena [83]

"The speed will increase" is the one among the following choices given in the question that describes the speed of a wave traveling through the rope, if <span>the tension in a rope is increased. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that has come to your help.</span>

5 0

3 years ago

Read 2 more answers

A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset vo

kiruha [24]

Answer:

The value is $V_{os} = 0.001 \ V$

Explanation:

From the question we are told that

The circuit resistance is $R_1 = 10 \ k \Omega$

The feedback resistance is $R_f = 220 \ k \Omega$

The offset current is $I_{os } = 100 \ nA = 100 * 1)^{-9} \ A$

Generally the offset voltage is mathematically reparented as

$V_{os} = R_f * I_{os}$

=> $V_{os} = 10 *10^{3}* 100 *10^{-9}$

=> $V_{os} = 0.001 \ V$

6 0

3 years ago

If The density of this stainless steel is7.85 g/cm3,specific heatis 0.5 J/g.K, melting pointis 1673K, heat of fusion s0.260J/kg.

kodGreya [7K]

Answer:

$\Delta H=687.4 J$

Explanation:

Hello!

In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:

1. Heat up from 298.15 K to 1673 K.

2. Undergo the phase transition.

Both process have an associated enthalpy as shown below:

$\Delta H_1=1g*0.5\frac{J}{g*K} (1673K-298.15K)=687.4J$

$\Delta H_2=0.001kg*\frac{0.260J}{kg} =0.00026J$

Therefore, the required heat is:

$\Delta H=\Delta H_1+\Delta H_2\\\\\Delta H=687.4J+0.00026J\\\\\Delta H=687.4J$

Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.

Best regards!

4 0

2 years ago

Complete the ray diagram and label incident ray, refracted ray, angle of incidence, and angle of refraction

Novay_Z [31]

Answer:

Solution

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(a) The labelled diagram is shown.

(b) The refractive index of diamond is 2.42. Refractive index of diamond is the ratio of the speed of light in air to the speed of light in diamond.i.e.,

μ=

Speedoflightindiamond

Speedoflightinair

and, the ratio of these velocities is 2.42. i.e., This means that the speed of light in diamond will reduce by a factor of 2.42 as compared to its speed in air. In other words, the speed of light in diamond is

1/2.42

times the speed of light in vacuum.

Explanation:

a) Draw and label the diagram given :

(i) Incident ray

(ii) Refracted ray

(iii) Emergent ray

(iv) Angle of reflection

(v) Angle of deviation

(v) Angle of emergence

(b) The refractive index of diamond is 2.42. What is the meaning of this statement in relation to speed of light?