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Ber [7]
3 years ago
7

A road perpendicular to a highway leads to a farmhouse located 55 mile away. an automobile traveling on the highway passes throu

gh this intersection at a speed of 60mph.60mph. how fast is the distance between the automobile and the farmhouse increasing when the automobile is 77 miles past the intersection of the highway and the road? the distance between the automobile and the farmhouse is increasing at a rate of miles per hour.
Physics
1 answer:
saveliy_v [14]3 years ago
3 0

The answer in this question is 44.7533 mphGiven information which we denote I as the distance of the automobile between the farmhouse, and S = the distance past the intersection of the highway and the road. 
Then I^2 = 5^2 + s^2. Taking the derivative of both sides of this equation yields 2I(ds/dt) = 2s(ds/dt), so (dl/dt) = s(ds)/I(dt). When the automobile is 7 miles past the intersection we have;dl/dt = 55√(7/5^2 +7^2) and gives us the answer of approximately 44.7533 mph
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Find the area under the standard normal curve to the right of z=0.49. round your answer to four decimal places, if necessary.
VikaD [51]

Left of z = 0.49 and right of z = 2.05, the area underneath the standard normal curve is equal to 0.7081.

<h3>What is  the standard normal curve?</h3>

The horizontal axis is approached by the standard normal bend as it extends indefinitely both in directions without ever being touched by it. The center of the bell-shaped, z=0 standard normal curve. Between z=3 and z=3, almost the entire area underneath the standard normal curve is located.

<h3>Use of the standard normal curve:</h3>

Use the normal distribution's standard form to calculate probability. Since the standard normal distribution is indeed a probability distribution, the probability that a variable will take on a range of values is indicated by area of the curve between two points. 100% or 1 is the total area beneath the curve.

<h3>According to the given data:</h3>

the region to the left of the standard normal curve,

z=0.49

To the right of,

z = 2.05

So,

The area will be:

= P[z < 0.49] + P[ z >2.05]

= P[z < 0.49] + 1 -  P[ z < 2.05]

= .6879 + 1 - .9798

= 0.7081

Left of z = 0.49 and right of z = 2.05, the area underneath the standard normal curve is equal to 0.7081.

To know more about standard normal curve visit:

brainly.com/question/12972781

#SPJ4

I understand that the question you are looking for is:

Find the area under the standard normal curve to the left of z = 0.49 and to the right of z = 2.05. Round your answer to four decimal places, if necessary.

4 0
1 year ago
Conduction can only happen when objects are in:
serious [3.7K]

Answer:

When it’s gravitational

Explanation:

I’m pretty sure that’s the answer

5 0
2 years ago
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Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

   Pressure at sea level = 1 atm = 101300 Pa

   we know

   P = ρ g h

   h = \dfrac{P}{\rho\ g}

   h = \dfrac{101300}{1.3\times 9.8}

          h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

  at x = 0  air density = 0

  at x= h   ρ_l = ρ_sl

 assuming density is zero at x - distance

 \rho_x = \dfrac{\rho_{sl}}{h}\times x

now, Pressure at depth x

dP = \rho_x g dx

dP = \dfrac{\rho_{sl}}{h}\times x g dx

integrating both side

P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx

P =\dfrac{\rho_{sl}\times g h}{2}

 now,

h=\dfrac{2P}{\rho_{sl}\times g}

h=\dfrac{2\times 101300}{1.3\times 9.8}

  h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

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2 years ago
In the periodic table of elements, what do all of the elements in group 2 have in common?
Shkiper50 [21]
The correct answer is letter C.
6 0
3 years ago
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What provides the source of the earth’s magnetic field?
ololo11 [35]
<h2>Answer: the core of the earth</h2>

The explanation accepted by science until now, indicates that Earth's magnetic field is generated in the deepest of the terrestrial nucleus.

This is due to the movements of liquid metals in the core of the planet.

To explain it in more detail:

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The differences in temperature, pressure and composition within the outer core cause convection currents in the molten metal, as the cold, dense matter sinks, and the warm, less dense matter rises. In addition, the Coriolis force, resulting from the spin of the Earth, also causes eddies in this mixture of molten metals.

This is how the movement of liquid iron inside the Earth generates electric currents, which in turn produce magnetic fields, and the spiral caused by the Coriolis force causes the magnetic fields to align in approximately the same direction, being this combined effect added to produce a vast magnetic field that envelops the entire planet.

This field extends from the terrestrial nucleus, progressively attenuating itself in outer space. However, it should be noted that unlike the field of a bar magnet, the Earth's magnetic field changes over time because it is actually generated by the movement of the iron alloys in the Earth's outer core, which causes the poles to move.

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