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inna [77]
1 year ago
11

Find the area under the standard normal curve to the right of z=0.49. round your answer to four decimal places, if necessary.

Physics
1 answer:
VikaD [51]1 year ago
4 0

Left of z = 0.49 and right of z = 2.05, the area underneath the standard normal curve is equal to 0.7081.

<h3>What is  the standard normal curve?</h3>

The horizontal axis is approached by the standard normal bend as it extends indefinitely both in directions without ever being touched by it. The center of the bell-shaped, z=0 standard normal curve. Between z=3 and z=3, almost the entire area underneath the standard normal curve is located.

<h3>Use of the standard normal curve:</h3>

Use the normal distribution's standard form to calculate probability. Since the standard normal distribution is indeed a probability distribution, the probability that a variable will take on a range of values is indicated by area of the curve between two points. 100% or 1 is the total area beneath the curve.

<h3>According to the given data:</h3>

the region to the left of the standard normal curve,

z=0.49

To the right of,

z = 2.05

So,

The area will be:

= P[z < 0.49] + P[ z >2.05]

= P[z < 0.49] + 1 -  P[ z < 2.05]

= .6879 + 1 - .9798

= 0.7081

Left of z = 0.49 and right of z = 2.05, the area underneath the standard normal curve is equal to 0.7081.

To know more about standard normal curve visit:

brainly.com/question/12972781

#SPJ4

I understand that the question you are looking for is:

Find the area under the standard normal curve to the left of z = 0.49 and to the right of z = 2.05. Round your answer to four decimal places, if necessary.

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KIM [24]

Answer:

-6

Explanation:

FRICTIONAL force=-300N,NORMAL REACTION,R=+50.0

Ú=F/R

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3 0
2 years ago
When ____________________ equals the force of gravity on a falling object, the object reaches terminal velocity.
Lilit [14]

The correct answer to the question is : Air resistance.

EXPLANATION:

Before coming into any conclusion, first we have to understand the terminal velocity.

An object is said to be moving with terminal velocity if the net force acting on the object is zero i.e the body is non accelerating.

As per the question, the object is falling under gravity. The force of gravity acts in vertical downward direction.

Except gravity, the object is also under air resistance. It is the force which opposes the motion of the object, and acts in vertical upward direction.

If the air resistance becomes equal to force of gravity, then the net force acting on the object is zero . It is so because two forces act in opposite direction.

In case of liquids, the resistance force is called as viscosity.

Hence, the correct answer to the question is air resistance.



5 0
3 years ago
Now, consider whether the following statements are true or false:_____________________________________.
Igoryamba

Answer:

A)F

B)F

C)T

Explanation:

A)

This is not always true that the product of the two vector's always non-negative .It may be positive or negative.

That is why this statement is false.

B)

The unit vectors in three perpendicular direction is i ,j and k.

We know that for unit vectors

i.i=j.j=k.k= 1

i .j= j.k=k.i=0

Therefore only  parallel component of the force will contribute in the integral part instead of perpendicular component of the force.

That is why this statement is false.

C)

This statement is True.

A)F

B)F

C)T

7 0
3 years ago
A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kin
riadik2000 [5.3K]

Answer:

a = 0.1 m/s²

Explanation:

  • If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.
  • Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:

       F_{net}  = F_{app} -F_{frk}  = 100 N - 70 N = 30 N (1)

  • By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:

       F_{net} = m* a = 300 Kg * a = 30 N (2)

  • Solving for a:

        a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)

5 0
3 years ago
At a given time of​ day, the ratio of the height of an object to the length of its shadow is the same for all objects. If a 4​-f
katrin2010 [14]

Answer:35.2 ft

Explanation:

Given

height of stick =4 ft

shadow length =2.8 ft

Angle of elevation of sun is

tan\theta =\frac{4}{2.8}

let the height of tree be h

as \thetawill remain same thus

tan\theta =\frac{h}{24.64}

\frac{4}{2.8}=\frac{h}{24.64}

h=35.2 ft

8 0
3 years ago
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