You are presently taking a weather observation. The sky is full of wispy cirrus clouds estimated to be about 10 km overhead. If
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Answer:
Net torque,
Explanation:
It is given that,
Initial angular speed of the blade,
Final angular speed of the blade,
Time, t = 18 s
Radius of the disk, r = 0.13 m
Mass of the disk, m = 0.4 kg
We need to find the net torque applied to the blade. We know that in rotational mechanics the net torque acting on an object is equal to the product of moment of inertia and the angular acceleration such that,
The moment of inertia of the disk,
Negative sign shows that the net torque is acting in the opposite direction of its motion. Hence, this is the required solution.
Answer:
(a) The current needed is 56.92 A
(b) The magnitude of the magnetic field inside the solenoid is 0.134 T
(c) The energy density inside the solenoid is 7.144 kJ/m³
Explanation:
Given;
energy stored in the magnetic field of solenoid, E = 8.1 J
number of turns of the solenoid, N = 620 turns
diameter of the solenoid, D = 6.6 cm = 0.066 m
radius of the solenoid, r = D/2 = 0.033 m
length of the solenoid, L = 33 cm = 0.33 m
Inductance of the solenoid is given as;
where;
A is the area of the solenoid = πr² = π (0.033)² = 0.00342 m²
μ₀ is permeability of free space = 4π x 10⁻⁷ H/m
(A). How much current needed
Energy stored in magnetic field of solenoid is given as;
Where;
I is the current in the solenoid
(B) The magnitude of the magnetic field inside the solenoid
B = μ₀nI
where;
n is number of turns per unit length
B = μ₀(N/L)I
B = (4π x 10⁻⁷)(620/0.33)(56.92)
B = 0.134 T
(C) The energy density (energy/volume) inside the solenoid
See attached file:
We are given the electric field equation so we input all the values we are given, eventually getting E = 51.75 N/C
We are given the electric field equation so we input all the values we are given, eventually getting E = 51.75 N/C