All categories

2 years ago

Please help me with question 7. Thank you so much.

Chemistry

1 answer:

tigry1 [53]2 years ago

4 0

Answer:

The system is not at equilibrium and the reaction will proceed to the left.

Explanation:

Step 1: Write the balanced equation

H₂(g) + CO₂(g) ⇄ CO(g) + H₂O(g)

Step 2: Calculate the reaction quotient (Q)

The reaction is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.

Q = [CO] × [H₂O] / [H₂] × [CO₂]

Q = 0.610 × 0.695 / 0.425 × 0.500 = 2.00

Since Q ≠ Kc, the reaction is not at equilibrium.

Since Q > Kc, the reaction will proceed to the left.

You might be interested in

For the oxidation-reduction reaction equation given here 4ga+p4 indicate how many electrons are transferred in the formation of

sergij07 [2.7K]

The reaction given is:

4Ga + P4 ---> 4GaP

The oxidation number of the reactants is zero, because they are pure elements.

The P in compounds may have oxidation states 3- or 5-. Gallium may only have oxidation state 3+.

Then, to be neutral in GaP the oxidation states are 3+ for Ga and 3- for P.

And the transference of electrons can be see in this oxidation - reduction equations:

Ga (0) - 3 e- ----> Ga (3+)

P (0) + 3e- ---> P (3-)

So, for one formula unit, 3 electrons have been transfered from each Ga atom to P atom to form one GaP unit.

Answer: 3 electrons.

3 0

3 years ago

Acid base reaction is called nuetralization reaction why?

Lesechka [4]

Answer:

Explanation:

You have an acid that is acidic or a base that is basic. When you mix the two, they form water (assuming those are bronsted-lowry acids and bases) which is neutral.

3 0

3 years ago

Read 2 more answers

Watersheds are sloped areas of land that ?

luda_lava [24]

A. Channel precipitation runoff into bodies of water.

8 0

3 years ago

Read 2 more answers

Explain how low atomspheric oxygen levels affected alligators growth in terms of celluar respiration

Paraphin [41]

Answer:

Answer: Hyperoxic alligators show significantly lower breathing rates than their siblings in normoxic and hypoxic groups. Conversely, each breath supports greater oxygen consumption in hyperoxic animals than in other groups. Statistical significance between groups was calculated by ANOVA with post hoc Tukey-Kramer

3 0

2 years ago

Consider the intermediate chemical reactions. 2 equations. First: upper C a (s) plus upper C upper O subscript 2 (g) plus one ha

DochEvi [55]

<u>Answer:</u> When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

$CaO(s)+CO_2\rightarrow CaCO_3(s)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)$ $\Delta H_1=-812.8kJ$

(2) $2Ca(s)+O_2(g)\rightarrow 2CaO(s)$ $\Delta H_2=-1269kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]$

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

3 0

2 years ago