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Vsevolod [243]
3 years ago
9

3. How many moles are present in 100 g of Ca(NO3)2? PLEASEEE HELP ASAPP

Chemistry
2 answers:
Pavel [41]3 years ago
7 0

0Answer:<u><em> 0.6094</em></u>

Explanation:

no of moles = mass / molar mass = 100/164.088= 0.6094 mole

Luda [366]3 years ago
4 0

Answer:

0.609 moles

Explanation:

mass in g ÷ atomic mass = moles

Ca(NO₃)₂ = 1 Ca 40.078 amu

2 N 28.0134 amu

+ 6 O 95.994 amu

____________________

164.0854 amu

100 g ÷ 164.0854 amu = 0.609 moles

three significant digits

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