Answer:
25 mol
Explanation:
2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 18H₂O
The equation tells us that 25 mol O₂ generate 18 mol H₂O.
Answer:
V₂ = 568.9 mL
Explanation:
Given data:
Initial volume of gas = 550 mL
Initial pressure of a gas = 960 mmHg
Initial temperature = 200.0°C
Final volume = ?
Final pressure = 830 mmHg
Final temperature = 150°C
Solution:
Initial temperature = 200.0°C ( 200+273 = 473 K)
Final temperature = 150°C (150+273 = 423 K)
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 960 mmHg × 550 mL × 423 K / 473 K ×830 mmHg
V₂ = 223344000 mL / 392590
V₂ = 568.9 mL
Answer:
The correct option is: B) 2nd order
Explanation:
The rate law equation of a chemical reaction is a mathematical expression which expresses the relationship of the rate of the chemical reaction with concentration of reactants. The overall order of the reaction is equal to the sum of orders with respect to all the reactants in the rate law equation.
The given reaction: NO(g) + O₃(g) → NO₂(g) + O₂(g)
Rate = k[NO][O₃]
Therefore, the given chemical reaction is second order.