Answer:
26.5 g
Explanation:
First we convert 100.0 mL to L:
- 100.0 mL / 1000 = 0.100 L
Now we <u>calculate how many moles of sodium carbonate are needed</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- moles = molarity * liters
- 2.5 M * 0.100 L = 0.25 mol
Finally we <u>convert 0.25 moles of sodium carbonate into grams</u>, using its <em>molar mass</em>:
- 0.25 mol * 106 g/mol = 26.5 g
It is usually neutral becase its is close to neutral number 7
I believe transition metals are coinage metals. The answer should be A.
<span>You are given O2 and C3H8, this is a combustion
reaction. The chemical reaction is C3H8 + 10O2 à 3CO2 + 4H2O. You are also given the molar mass
of O2 which is 32.00 g/mol and C3H8 which is 44.1 g/mol. You are required to
find the mass of O2 in grams. Since you have the reaction, oe mole of C3H8 is
required to completely react 10 moles of O2. So,</span>
0.025g C3H8(1 mol C3H8/44.1 g C3H8)(10 mol O2/1
mol C3H8)(32 g O2/1 mol O2) = <u>0.1802 g O2
</u>
<span> </span>
