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Irina18 [472]
3 years ago
7

Many types of decorative lights are connected in parallel. If a set of lights is connected to a 110 V source and the filament of

each bulb has a hot resistance of what is the currentthrough each bulb
Physics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

i₀ = V / R_i

Explanation:

For this exercise we use Ohm's law

         V = i R

          i = V / R

the equivalent resistance for

         \frac{1}{R_{eq}} =  ∑ \frac{1}{R_i}

if all the bulbs have the same resistance, there are N bulbs

         \frac{1}{ R_{eq}} = \frac{N}{R_i}

         R_{eq} = R_i / N

we substitute

         i = N V / Ri

where i is the total current that passes through the parallel, the current in a branch is

         i₀ = i / N

         i₀ = V / R_i

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If the primary of a transformer were connected to a dc power source,
QveST [7]

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D. only briefly while being connected or disconnected.

Explanation:

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here we know that as per the principle of mutual inductance when flux linked with the primary coil charges then it will induce EMF in secondary coil

So here when AC source is connected with primary coil then it will give output across secondary coil because AC source will have change in flux with time.

Now when we connect DC source across primary coil then it will not induce any EMF across secondary coil because DC source is a constant voltage source in which flux will remain constant always

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At its maximum speed, a typical snail moves about 4.0 m in 5.0 min.
stiv31 [10]

Answer:

Explanation:

Given

Distance = 4.0m

Time = 5.0 mins = 300secs

Required

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Average speed = Distance/Time

Average speed = 4.0/300

Average speed = 0.01333m/secs

Hence the average speed of the snail is 0.01333m/s

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A radio have a wavelength of 0.3m and travels at a speed of 300,000,000 m/s. What is the frequency of this wave?​
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Explanation:

The frequency, the wavelength and the speed of a wave are related by the following equation:

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c is the speed of the wave

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\lambda is the wavelength

For the radio wave in this problem,

\lambda = 0.3 m

c=300,000,000 m/s = 3\cdot 10^8 m/s

Therefore, the frequency is:

f=\frac{c}{\lambda}=\frac{3\cdot 10^8}{0.3}=1\cdot 10^9 Hz

Learn more about waves here:

brainly.com/question/5354733

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#LearnwithBrainly

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