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Alexandra [31]
3 years ago
11

How and why ions form. Give examples of both metals and no metals

Chemistry
1 answer:
Vinvika [58]3 years ago
4 0
Im sorry , Im confused reading this . maybe enter a image ?
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Using your knowledge of the difference
ElenaW [278]
The person would die. Degrees Celsius is much higher than degrees Fahrenheit, therefore if the temperature rises 1 degrees celsius that’s much more of a rise than 1 degree Fahrenheit .
4 0
3 years ago
Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrate
Phoenix [80]

The question is incomplete , complete question is :

Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrated (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =31.5

Given: [TZ] = 0.5461 mol/L

Answer:

The concentration of TZ solution in μmol/L is 546 μmol/L

Explanation:

Molarity of the TZ solution = 0.5461 mol/L

This means that 0.5461 moles of TZ are present in 1 L of solution.

Moles of TZ = 0.5461 mol

mol= 1000 \mu mol

0.5461 mol=0.5461\times 1000 \mu mol=546.1 \mu mol

So, the concentration of TZ solution in μmol/L is :

546.1 μmol/L ≈ 546 μmol/L

7 0
3 years ago
What is the Kelvin temperature for 30°C?
Annette [7]
303.15 would be your answer 
4 0
3 years ago
How many moles of hydrogen molecules (h2) are present in 9 x 1023 molecules of hydrogen?
Marta_Voda [28]
Hello

So the molar mass of a Hydrogen molecule is 2. If you have 10 grams of Hydrogen molecules, you have 5 moles<span> of Hydrogen molecules (10 moles of Hydrogen atoms). Avogadro's number is 6.0225x10^23. This means that </span>one mole<span> of a substance has that many particles.
</span>
Have a nice day 
7 0
3 years ago
Read 2 more answers
For the reaction Fe3O4(s) + 4H2(g) --&gt; 3Fe(s) + 4H2O(g)
mojhsa [17]

Answer : The value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = 151.2 kJ = 151200 J

\Delta S^o = standard entropy = 169.4 J/K

T = temperature of reaction = 328.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(151200J)-(328.0K\times 169.4J/K)

\Delta G^o=95636.8J=95.6kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

95636.8J=-(8.314J/K.mol)\times (328.0K)\times \ln k

k=1.70\times 10^{15}

Therefore, the value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

3 0
3 years ago
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