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Mekhanik [1.2K]
3 years ago
6

Help me with this please

Physics
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

i dont understand, can you put it in word form please.

Explanation:

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Will both buzzers sound in this circuit?
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QUESTION:

Will both buzzers sound in this circuit?

ANSWER:

No, Only first buzzer sound. It is because the 2nd buzzer doesn't connected.

6 0
3 years ago
If you were on the moon, and you were trying to move a 20-lb bowling ball and a 3-foot cube of Styrofoam, which item would take
laila [671]
I think it is C since the mass will stay the same except not the gravity
5 0
4 years ago
Read 2 more answers
A plane lands and comes to a complete stop through 180 m of runway with a deceleration of 6.25 m/s2 [N]. Determine the plane’s v
oksano4ka [1.4K]

Answer:

47.43 m/s

Explanation:

Given that,

Final speed of a plane, v = 0

Distance, d = 180 m

Acceleration of the plane, a = -6.25 m/s² (deceleration )

We need to find the plane's velocity. Let it was u. So, using the third equation of kinematics as :

v^2-u^2=2ad\\\\u^2=0^2-2\times (-6.25)\times 180\\\\u=\sqrt{2250} \\\\u=15\sqrt{10}\ m/s\\ \\\text{or}\\\\u=47.43\ m/s

So, the plane's velocity when it first touched the landing strip is 47.43 m/s.

4 0
3 years ago
Which does a reference point provide? Check all that apply.
Inessa05 [86]
A reference point Is simply all in which your following endeavours are based on
meaning this cannot be modified since it's what you based YOURS on!
hope this helps
5 0
3 years ago
A 1.70 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1
Nikitich [7]
Resistance = ρ * (L/A) and Rf = Ri * ([1 + α * (Tf – Ti)] 
ρ = Resistivity L = length in meters A = cross sectional area in m^2 α = temperature coefficient of resistivity 
L = 1.50 m Area = π * r^2 r = d/2 = 0.25 cm = 2.5 * 10^-3 m Area = π * (2.5 * 10^-3)^2 

The cylindrical rod is similar to a resistor. Since the current is decreasing, the resistance must be increasing. This means the resistance is increasing as the temperature increases. Resistance = Voltage ÷ Current At 20˚, R = 15 ÷ 18.5 At 92˚, R = 15 ÷ 17.2 

Now you know the resistance at the two temperatures. Let’s determine the resistivity at the two temperatures. Resistance = ρ * (L/A) ρ = Resistance * (A/L) 
At 20˚, ρ = (15 ÷ 18.5) * [π * (2.5 * 10^-3)^2] ÷ 1.5 = At 92˚, ρ = (15 ÷ 17.2) * [π * (2.5 * 10^-3)^2] ÷ 1.5 = 
Now you know the resistivity at the two temperatures. Let’s determine the temperature coefficient of resistivity for the material of the rod. 
Rf = Ri * ([1 + α * (Tf – Ti)] Rf = 15 ÷ 17.2, Ri = 15 ÷ 18.5, Tf = 92˚, Ti = 20˚ 
15 ÷ 17.2 = 15 ÷ 18.5 * [1 + α * (92 – 20)] Multiply both sides by (18.5 ÷ 15) (18.5 ÷ 15) * (15 ÷ 17.2) = 1 + α * 72 Subtract 1 from both sides (18.5 ÷ 15) * (15 ÷ 17.2) – 1 = α * 72 Divide both sides by 72 α = 1.05 * 10^-3 
4 0
3 years ago
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