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Zepler [3.9K]
3 years ago
9

Do you have a sample of read, draw and write problems for 4th grade math to review for a test?

Mathematics
1 answer:
swat323 years ago
5 0
I’ll check if I do
I might
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Mary leaves her house to take a walk. The graph shows the distance, d, in feet from her house that Mary is at any given time, t,
Mkey [24]

Answer:

It would be option A. 10 Minutes.

Step-by-step explanation:

If you look at the graph, the farthest point, and the time of 10 minutes meet at the point (10, 2,500)

(Really hoping this helps <3)

7 0
3 years ago
esse deposits $428 into his new checking account. During the month, he deposits $40 and withdraws $25, $283, and $119. What is t
tatyana61 [14]
A $1 is all he has left.
7 0
3 years ago
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11. Find the Percent of Change (Round to the nearest tenth if necessary)
Elanso [62]

Answer:

A. 5.2% Decrease

Step-by-step explanation:

6 0
2 years ago
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
Solve a,b,c,d and e.​
Westkost [7]

Answer:

Step-by-step explanation:

a)

 428721

Place of 2's 10s and 10,000s

Therefore its value is 20 and 20,000

Product of the place value = 20 x 20,000 = 4,00,000

b)

37,20,861

Place of 7 is 1,00,000

Therefore the place value is 7,00,000

c)

Greatest 7 digit number is 99,99,999

Adding 1 to it = 99,99,999 + 1 = 1,00,00,000

d)

85642 = 80000 + 5000 + 600 + 40 +2

e)

round off 85642  to nearest thousand = 86,000

7 0
2 years ago
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