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3 years ago

Which statement BEST describes the process of playing sports?

Physics

2 answers:

irina1246 [14]3 years ago

4 0

Answer:

Explanation:

DerKrebs [107]3 years ago

3 0

Answer:

option A because in sport pain makes a player strongest.......

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A test charge is introduced into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What wou

Firdavs [7]

Surrounding every charge (or group of charges) is a thing, called an electric field. (it is a vector thing). E. Definition: The electric field at a point. E in empty space is a vector quantity which can be measured by the following procedure: place a small test charge q at that point, measure the force on q due to all other charges.

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4 years ago

Read 2 more answers

An 870 N firefighter, F_ff, stands on a ladder that is 8.00 m long and has a weight of 355 N, F_ladder. The weight of the ladder

castortr0y [4]

Answer:

Explanation:

Weight of the ladder is 355N

WL = 355N

The weight of the ladder acts at center of the ladder I.e at 4m from the bottom

Weight of firefighters is 870N

Wf = 870N

The fire fighter is at 6.3m from the bottom of the ladder.

N1 is the normal force exerted by the wall

N2 is the normal force exerted by the ground

Using Newton law

Check attachment

ΣFy = 0, since body is in equilibrium

N₂ - WL - Wf = 0

N₂ = WL + Wf

N₂ = 870 + 355

N₂ = 1225 N

This the normal force exerted by the ground on the wall.

Now to get N₁, let take moment about point A

So, before we take the moment we need to make sure that the forces are perpendicular to the plane(ladder), we need to resolve the weight of the ladder, firefighter and the normal of the wall to be perpendicular to the plane.

ΣMa = 0

Clockwise moment is equal to anti-clockwise moment

Moment Is the produce of force and perpendicular distance.

M = F×r

So,

WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0

355•Cos50 × 4 + 870•Cos50 × 6.3 =

N₁•Sin50 × 8

1825.52 + 3523.12 = 6.13N₁

6.13N₁ = 5348.64

N₁ = 5348.64/6.13

N₁ = 872.54 N.

The normal force exerted by the wall is 872.54N

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3 years ago

An electric field of 6.1x 10^5 N/C is directed along a charge 2.9 x 10^-19 C. What

Aloiza [94]

Answer:

Electric field is a function 1/r^2

Explanation:

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3 years ago

Does light have to have a medium to pass through?

skad [1K]

Answer:

Light does not require any medium to travel because light is a transverse wave

hope it helps

7 0

3 years ago

a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we n

galina1969 [7]

Assuming the cannonball is fired horizontally, its horizontal velocity stays at a constant 76 m/s. At the point it hits the ground, it has a speed of 89 m/s, so if its vertical velocity at that moment is $v_y$ , we have

$89\dfrac{\rm m}{\rm s}=\sqrt{\left(76\dfrac{\rm m}{\rm s}\right)^2+{v_y}^2}\implies{v_y}^2\approx2145\dfrac{\mathrm m^2}{\mathrm s^2}$

(taking the negative square root because we take the downward direction to be negative)

Recall that

${v_f}^2-{v_i}^2=2a\Delta x$

where $v_i$ and $v_f$ are the initial and final velocities, respectively; $a$ is the acceleration; and $\Delta x$ is the change in position of a body. In the cannonball's case, it starts with 0 vertical velocity and is subject to a downward acceleration with magnitude $g=9.80\frac{\rm m}{\mathrm s^2}$ . So we have

$2145\dfrac{\mathrm m^2}{\mathrm s^2}-0=-2g\Delta y\implies\Delta y\approx-109.44\,\mathrm m$

(which is negative because we take the cannonball's starting position at the top of the cliff to be the origin) so the cliff is about 109 m high.

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3 years ago