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Marina86 [1]
3 years ago
13

A dart is thrown horizontally with an initial speed of 19 m/s toward point P, the bull's-eye on a dart board. It hits at point Q

on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ
Physics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

Explanation:

The dart will go forward horizontally with velocity of 19 m/s. It will also fall downwards with initial velocity of zero and gravitational acceleration of 9.8 m/s².

Distance PQ covered by the dart can be calculated using the following formula.

s = ut + 1/2 at²

u is initial velocity , a is acceleration and t is time.

Putting the values

s = 0 + 1/2 x 9.8 x .19²

= .1769 m

= 17.69 cm.

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gulaghasi [49]

Answer:

C

Explanation:

horizintal speed stays same

only vertical speed changes

so H speed will stay 30 m/s

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A bag of sugar weighs 3.50 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration isone-sixth
Alex73 [517]

Answer:

F_{Earth}= 15.57 N

F_{Moon}= 2.60 N

F_{Uranus}= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

Explanation:

The weight of the sugar bag on Earth is:

g=9.81 m/s²

m=3.50 lb=1.59 kg

F_{Earth}=m·g=1.59 kg×9.81 m/s²= 15.57 N

The weight of the sugar bag on the Moon is:

g=9.81 m/s²÷6= 1.635 m/s²

F_{Moon}=m·g=1.59 kg× 1.635 m/s²= 2.60 N

The weight of the sugar bag on the Uranus is:

g=9.81 m/s²×1.09=10.69 m/s²

F_{Uranus}=m·g=1.59 kg×10.69 m/s²= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

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3 years ago
How long does it take venus to orbit the sun
kodGreya [7K]
The answer is 225 days
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4 years ago
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How much force would be required to accelerate a 2kg object at a rate of 15m/ sec?
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An Olympic diver drops from the 10 meter platform with an initial velocity of 0.0m/s. What was the vertical velocity of the dive
sammy [17]

Answer:

v=14.14 m/s

t=1.141 s    

Explanation:

Given that

h = 10 m

Initial velocity ,u = 0 m/s

We know that acceleration due to gravity g= 10 m/s²

Lets take final velocity = v

Final velocity v is given as

v² = u²+ 2 g h

v²= 0² + 2 x 10 x 10

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Time taken t is given as

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Now by putting the values in the above equation we get

14.14= 0 + 10 x t

14.14 = 10 t

t=1.141 s

4 0
4 years ago
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