<h2>Answer: protons and neutrons.
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The atomic nuclei of almost all elements consist of protons and neutrons.
The nucleus of an atom has very small dimensions. However, it <u>occupies its central part and concentrates more than 99% of its total mass.
</u>
It is in the nucleus that the protons (positive charge) and neutrons (neutral charge) are found.
The gravitational force on the woman is A) 500 N
Explanation:
There are two forces acting on the woman during her fall:
- The force of gravity,
, acting downward - The air resistance,
, acting upward
According to Newton's second law, the net force acting on the woman is equal to the product between the woman's mass and her acceleration:

where m is the mass of the woman and a her acceleration.
The net force can be written as

Also, we know that the woman falls at a constant velocity (5 m/s), this means that her acceleration is zero:

Combining the equations together, we get:

which means that the magnitude of the gravitational force is equal to the magnitude of the air resistance:

Learn more about forces and Newton's second law:
brainly.com/question/3820012
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Answer:
Part a)
Mass of m2 is given as

Part b)
Angular acceleration is given as

Part c)
Tension in the rope is given as

Explanation:
Part a)
When m1 and m2 both connected to the cylinder then the system is at rest
so we can use torque balance here




Part b)
When block m_2 is removed then system becomes unstable
so force equation of mass m1

also we have

now we have




so angular acceleration is given as



Part c)
Tension in the rope is given as



Answer:
It should be fibre optic cable , buried underground
Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:
1 joule = 1watt * 1 second
or
E (energy) = P (power) * t (time duration)
E = 350 * 30 = 10500 joules.