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Doss [256]
2 years ago
11

48g of magnesium and 32g of oxygen react to form 80g of magnesium oxide.

Chemistry
1 answer:
ZanzabumX [31]2 years ago
3 0

Mass of Oxygen : 8 g

<h3>Further explanation</h3>

Given

48g of Magnesium

32g of Oxygen

Required

Mass of Oxygen

Solution

The ratio of Mg and O in MgO :

48 g : 32 g = 3 : 2

Total ratio = 3+2 = 5

So for 20 g MgO, mass of Oxygen :

=2/5 x 20 g

=8 g

Or

%mass O = 32/80 x 100%=40%

mass O in 20 g MgO =

40% x 20 g =8 g

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Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight
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Answer:

The final mass of sample is 1.3 g.

Explanation:

Given data:

Half life of H-3 = 12.32 years

Amount left for 15.0 years = 3.02 g

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Solution:

First all we will calculate the decay constant.

t₁/₂ = ln² /k

t₁/₂ =12.32 years

12.32 y =  ln² /k

k = ln²/12.32 y

k = 0.05626 y⁻¹

Now we will find the original amount:

ln (A°/A) = Kt

ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y

ln (3.02 g/ A) = 0.8439

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3.02 g/ A = 2.33

A = 3.02 g/ 2.33

A = 1.3 g

The final mass of sample is 1.3 g.

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Answer:

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Explanation:

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