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Doss [256]
3 years ago
11

48g of magnesium and 32g of oxygen react to form 80g of magnesium oxide.

Chemistry
1 answer:
ZanzabumX [31]3 years ago
3 0

Mass of Oxygen : 8 g

<h3>Further explanation</h3>

Given

48g of Magnesium

32g of Oxygen

Required

Mass of Oxygen

Solution

The ratio of Mg and O in MgO :

48 g : 32 g = 3 : 2

Total ratio = 3+2 = 5

So for 20 g MgO, mass of Oxygen :

=2/5 x 20 g

=8 g

Or

%mass O = 32/80 x 100%=40%

mass O in 20 g MgO =

40% x 20 g =8 g

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How many particles are in 47.7 g of Magnesium? (Round the average
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Answer:

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General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
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Explanation:

<u>Step 1: Define</u>

47.7 g Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

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<u>Step 3: Convert</u>

<u />47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} ) = 1.18161 × 10²⁴ particles Mg

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

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