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guapka [62]
3 years ago
12

A neutral atom of Cobalt (Co) has an atomic number of 27 and an atomic mass of 59. Therefore, Co has _________________________

Chemistry
1 answer:
stepladder [879]3 years ago
3 0

Answer:

A neutral atom of Cobalt (Co) has an atomic number of 27 and an atomic mass of 59. Therefore, Co has 27 electrons, 27 protons and 32 neutrons.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

The atomic number Co is 27 it means it has 27 protons and 27 electrons.

The mass number is sum of protons and neutrons, thus number of neutrons are

59 - 27 = 32 neutrons

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The chemical equation shows iron(III) phosphate reacting with sodium sulfate. 2FePO4 + 3Na2SO4 Fe2(SO4)3 + 2Na3PO4 What is the t
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<u>Answer:</u> The theoretical yield of iron(III) sulfate is 26.6 grams

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

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Putting values in equation 1, we get:

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2FePO_4+3Na_2SO_4\rightarrow Fe_2(SO_4)_3+2Na_3PO_4

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2 moles of iron(III) phosphate produces 1 mole of iron(III) sulfate

So, 0.133 moles of iron(III) phosphate will produce = \frac{1}{2}\times 0.133=0.0665moles of iron(III) sulfate

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Molar mass of iron(III) sulfate = 399.9 g/mol

Moles of iron(III) sulfate = 0.0665 moles

Putting values in equation 1, we get:

0.0665mol=\frac{\text{Mass of iron(III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron(III) sulfate}=(0.0665mol\times 399.9g/mol)=26.6g

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